java - 初始化问题

Question

private void northroom()
{
    char choice2;
    boolean boolean_1 = false;
    String answer2;
    System.out.println("You press a panel next to the door");
    System.out.println("The panel lights up with a pinging sound");
    System.out.println("The door slowly scrapes open");
    System.out.println("You are now in North Room");
    System.out.println("There is a object in the coner of the room shoraded by darkness");
    do
    {
        System.out.println("Would you like to pick up object Yes(Y) or No(N)");
        while(boolean_1 == false)
        {

            answer2 = keyboard.next();
            choice2 = answer2.charAt(0);
            if(choice2 == 'Y')
            {
                System.out.println("You go pick up the object");
            }
            if(choice2 == 'N')
            {
                    System.out.println("Stare at object because you are useless");
                    System.out.println("Try again");
            }
        }
    } 
    while (**choice2** != 'Y' && **choice2** != 'N');

while (选择2 != 'Y' && 选择2 != 'N');

这里两个 choice2 都已初始化，我该如何纠正它以使其正确循环

Answer 1

编译器代码路径分析器还不足以识别 while(boolean_1 == false) 循环将始终至少执行一次。

就编译器而言，循环体可能会被跳过，在这种情况下，choice2 变量未分配，即未明确分配。

您可以通过将其初始化为虚拟值来解决此问题，例如

char choice2 = ' ';

当然，如果编译器进行了扩展分析，它会发现 while(boolean_1 == false) 循环会永远运行，因为 boolean_1 永远不会更新，并会生成编译错误，指出 while (choice2 != 'Y' && choice2 != 'N'); 无法访问。