java - Java-ArrayOutOfBoundsException帮助我

Question

import java.util.*;

import java.util.Arrays;

public class ScoreCalc {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        char[] alphabet = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
        int[] score = {1,3,3,2,1,4,2,4,1,8,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10};
        System.out.println("Enter word: ");
        String word = in.nextLine();
        int totalScore = 0;
        char[] wordArray = word.toCharArray();
        for(int i=0; i<wordArray.length; i++) {
            System.out.println(wordArray[i]);
            int index = Arrays.asList(alphabet).indexOf(wordArray[i]);
            System.out.println(index);
            totalScore = totalScore + score[index];
        }
        System.out.println(totalScore);
    }
}

这会在线程“main”中不断抛出异常java.lang.ArrayIndexOutOfBoundsException:-1

因为找不到数组字母表中的任何字符，所以有人可以帮助plz!

Answer 1

indexOf(wordArray[i])返回-1。我怀疑这是由于大写字母和/或特殊字符引起的。首先执行此操作并添加错误检查:

word.toLowerCase().toCharArray()

无论如何，我会做这样的事情，因为它更干净:

String alphabet = "abcdefghijklmnopqrstuvwxyz";

接着

int index = alphabet.indexOf(wordArray[i]);
if(index == -1) {
    // handle the special character
} else {
    totalScore += score[index];
}