java.sql.SQLException : Column Index out of range, 2 > 1

Question

我有一条我不明白的错误消息。该消息是下一个“java.sql.SQLException:列索引超出范围，2 > 1”请问我的问题是不是来 self 的请求sql？

String req = "Select A.CodeA from album A, collabo C where A.CodeA = C.CodeA order by 1 ";
        ResultSet resu = ConnexionMySQL.getInstance().selectQuery (req);
        try {
            while (resu.next())
            {  
                myList.add (new Appareil(resu.getString(1), 
                             new Album (resu.getString(2))));

             }
        }

或者也许在我的文件 TableModel Appareil 中？我有一列“标识”，只是我不明白为什么它不起作用？

private String[] columnNames = {"Identification"};
    private ArrayList <Appareil> myList;

    public TableModelAppareils (ArrayList myList)
    {
        this.myList = myList;
    }

    public int getColumnCount() {
        return columnNames.length;
    }

    public int getRowCount() {
        //System.out.println("row count : " + myList.size());
        return myList.size();
    }

    @Override
    public String getColumnName(int col) {
        return columnNames[col];
    }

    @Override
    public Object getValueAt(int row, int col) {
        Appareil myApp = myList.get(row);
        switch (col)
        {
            case 0 :    return myApp.getAppAlb().getCodeA();
        }
        return null;
    }

    @Override
    public Class getColumnClass(int c) {
        switch (c)
        {
            case 0 :    return String.class;

        }
        return null;
    }

    public void setMyList (ArrayList myList)
    {
        this.myList = myList;
        this.fireTableDataChanged();
    }

    public ArrayList <Appareil> getMyList ()
    {
        return myList;
    }

    public Appareil getMyList (int index)
    {
        return myList.get(index);
    }

非常感谢

Answer 1

您正在代码中使用 resu.getString(2) 访问 ResultSet 中的第二列，但您只选择了一列 A.codeA 在您的选择查询中