java - 在一行中绘制多个矩形

Question

我正在尝试制作一个游戏，如果球击中一个矩形，该矩形的值就会下降，一旦达到 0，它就会消失。我还没有实现计数变量，但遇到了问题，我试图渲染顶部的数组列表，但当我尝试绘制多个矩形并将它们留在那里时，我的循环仅渲染一个对象球可以与之发生 react 。我该怎么做？

package graphics;

import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;

public class Ballz extends LASSPanel
{
//Variables for the circle (Global Variables)

int circleX, circleY, circleSize;
double ballDirection,circleDX, circleDY;


//Colors
Color circleColor;
Color backgroundColor;
Dimension size;

int turn = 1;
int click =0;
int go =0;
int move = 0;
boolean roundEnd;



//Variables for the map
int brickWH;
int[] rect = new int[12];



public Ballz()
{
    //Ball Variables
    size = new Dimension(0,0);


    circleX = 190;
    circleY = 545;
    circleDX = 0;
    circleDY=0;

    circleSize = 15;

    circleColor = new Color (245,245,245);
    backgroundColor = new Color (28,28,28);

    //Game Variables
    roundEnd = true;

    brickWH = 18;
}

public void update()
{
    //Get size of screen
    getSize(size);




    circleX += circleDX;
    circleY += circleDY;



    //Screen borders
    if (circleX >= (size.width) - circleSize)
    {
        circleDX = -circleDX;
        circleX = size.width-circleSize;

    }
    if (circleX <= 0)
    {
        circleDX = -circleDX;
        circleX = 0;
    }
    if (circleY >= (size.height -circleSize))
    {
        circleDX =0;
        circleDY = 0;
        circleX = 190;
        circleY = 545;
        roundEnd = true;
    }
    if (circleY <= 0)
    {
        circleDY = -circleDY;
        circleY = 0;
    }


    circleX += circleDX;
    circleY += circleDY;


    click = getMouseButton(0);

    if (click ==1)
    {
        circleDY = -5;
        circleDX = -3;
    }


    //Rectangle Loop


    for (int i =0; i<rect.length; i++)
    {
        rect[i] = rect[i] +50;
    }





    repaint();

}

public void paint(Graphics g)
{


    //Game Colors
    g.setColor(circleColor);
    g.fillOval(circleX, circleY, circleSize, circleSize);


    for (int i=0; i<rect.length; i++)
    {
        g.fillRect(rect[i], 2, brickWH, brickWH);

    }

    setBackground(backgroundColor); 







}

}

Answer 1

好的，看过更多代码后，让我们开始......

int[] rect = new int[12];

这会创建一个 int 数组，最初初始化为所有 0

接下来，你...

for (int i =0; i<rect.length; i++)
{
    rect[i] = rect[i] +50;
}

所有这一切基本上都是将 50 添加到 0 并将其分配回数组元素，所以当您这样做时...

for (int i=0; i<rect.length; i++)
{
    g.fillRect(rect[i], 2, brickWH, brickWH);

}

它只是将每个“砖 block ”绘制在最后一个“砖 block ”之上，因为它们都处于相同的水平位置

对我来说真正非常非常突出的是......

for (int i =0; i<rect.length; i++)
{
    rect[i] = rect[i] +50;
}

您的意图是让每 block 砖 block 相距 50 像素吗？在这种情况下，你可能应该做一些更像......

int xPos = 0;
for (int i =0; i<rect.length; i++)
{
    rect[i] = xPos;
    xPos += 50;
}

如果相反，它们应该放在一起，那么您会想要更像......的东西

for (int i =0; i<rect.length; i++)
{
    rect[i] = brickWH * i;
}