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java - 输入不匹配异常错误

转载 作者:行者123 更新时间:2023-12-02 11:04:27 25 4
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我收到输入不匹配错误,但不知道为什么。它正在另一台计算机上工作,但似乎无法在我的笔记本电脑上工作。起初我以为可能是我的txt文件,但这不是原因。

import java.io.*;
import java.util.*;
public class FindGrade {
public static final int NUM_SCORE_TYPES = 5;

public static void main(String[] args) {
Scanner scan = null;
int[] quizArray = null;
int[] labArray = null;
int[] attendance = null;
int[] midterms = null;
int quizgrade =0;
int labgrade=0;
int attendance_1=0;
int midterms_1 =0;
String name;


try {
scan = new Scanner(new File("input.txt"));
} catch (FileNotFoundException e) {
e.printStackTrace();
return;
}

// each iteration is for single exam type (ie: Quizzes is the 1st one)
for (int i = 0; i < NUM_SCORE_TYPES; i++) {

name = scan.next();
int numScores = scan.nextInt();
int maxGrade = scan.nextInt();

if (name.equals("Quizzes")) {
quizArray = new int[numScores];
readScores(quizArray, numScores, scan);


}

else if (name.equals("Labs")) {
labArray = new int[numScores];
readScores(labArray, numScores, scan);

}
else if (name.equals("Lab_attendance")) {
attendance = new int[numScores];
readScores(attendance, numScores, scan);

}
else if (name.equals("Midterms")) {
midterms = new int[numScores];
readScores(midterms, numScores, scan);

}

}

}


public static void readScores(int[] scoreArray, int numScores, Scanner scan) {
for (int i = 0; i < numScores; i++) {
scoreArray[i] = scan.nextInt();
}
}

public static void average(double [] scoreArray, int numScores){
double sum=0;
for(int i=0; i< scoreArray.length; i++){
sum += scoreArray[i];
}
double average = sum/numScores;

System.out.println(sum + " " + average);



}

}

输出:
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:840)
at java.util.Scanner.next(Scanner.java:1461)
at java.util.Scanner.nextInt(Scanner.java:2091)
at java.util.Scanner.nextInt(Scanner.java:2050)
at FindGrade.main(FindGrade.java:33)

输入文件:
Quizzes 8 10
5 8 9 10 4 0 10 7
Labs 6 100
95 90 100 87 63 92
Lab_attendance 16 1
1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1
Midterms 2 100
87 94
Final 0 100

最佳答案

您的代码可以很好地处理您发布的数据。
如果将给变量“名称”分配的值与您期望的5个名称不同,如“测验”而不是“测验”,则会出现此错误。
在这种情况下,您的代码逻辑将被破坏,并且将出现此错误。这是可能的根本原因。

关于java - 输入不匹配异常错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21593920/

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