c - 错误: assignment to expression with array type in c

Question

我正在使用此功能来创建一个链表，其中每个节点都是完整牌组中的一张牌，但是我遇到了这个奇怪的错误。有什么帮助吗？

typedef struct cards
{
  char card[3];
  struct cards * next;
} cards_t;

cards_t * make_list(char ** deck) //function to make list
{
   int j = 0;
   cards_t *head = malloc (sizeof(cards_t));

   for (cards_t * iterator = head; j<52; iterator = iterator->next, j++)
   {
      iterator->card = deck[j];
      iterator->next = malloc(sizeof(cards_t));
   }

   return head;
} 

Answer 1

您必须通过char复制字符串char或使用string.h中的复制功能。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct cards
{
  char card[3];
  struct cards * next;
} cards_t;

cards_t * make_list(char ** deck) //function to make list
{
   int j = 0;
   cards_t *head = malloc (sizeof(cards_t));

   for (cards_t * iterator = head; j<52; iterator = iterator->next, j++)
   {
      strcpy(iterator->card,deck[j]);
      iterator->next = malloc(sizeof(cards_t));
   }

   return head;
}