regex - 将标点符号转换为空格

Question

我有一堆带标点符号的字符串，我想将其转换为空格:

"This is a string. In addition, this is a string (with one more)."

会变成:

"This is a string  In addition  this is a string  with one more  "

我可以使用 stringr 包 (str_replace_all()) 手动执行此操作，一次一个标点符号 (,/./!/(/)/等)，但我很好奇是否有更快的方法，我假设使用正则表达式。

有什么建议吗？

Answer 1

x <- "This is a string. In addition, this is a string (with one more)."
gsub("[[:punct:]]", " ", x)
[1] "This is a string  In addition  this is a string  with one more  "

请参阅 ?gsub 进行此类快速替换，并参阅 ?regex 了解有关 [[:punct:]] 类的详细信息，即

‘[:punct:]’ Punctuation characters:
      ‘! " # $ % & ' ( ) * + , - . / : ; < = > ? @ [ \ ] ^ _ ` { |
      } ~’.