r - 通过 k 均值聚类对 ggplot 的绘图矩阵进行着色？

Question

我正在尝试使用 ggplot2 创建 6 个数据变量的对图，并根据它们所属的 k 均值簇为点着色。我阅读了令人印象深刻的“GGally”包的文档以及 Adam Laiacano 的非正式修复 [http://adamlaiacano.tumblr.com/post/13501402316/colored-plotmatrix-in-ggplot2]。不幸的是，我找不到任何方法来获得所需的输出。

这是示例代码:-

#The Swiss fertility dataset has been used here

data_ <- read.csv("/home/tejaskale/Ubuntu\ One/IUCAA/Datasets/swiss.csv", header=TRUE)
data_ <- na.omit(data_)

u <- c(2, 3, 4, 5, 6, 7)
x <- data_[,u]
k <- 3
maxIterations <- 100
noOfStarts <- 100
filename <- 'swiss.csv'

library(ggplot2)
library(gridExtra)
library(GGally)

kmeansOutput <- kmeans(x, k, maxIterations, noOfStarts)

xNew <- cbind(x[,1:6], as.factor(kmeansOutput$cluster))
names(xNew)[7] <- 'cluster'
kmeansPlot <- ggpairs(xNew[,1:6], color=xNew$cluster)

OR

kmeansPlot <- plotmatrix(xNew[,1:6], mapping=aes(colour=xNew$cluster))

这两个图均已创建，但未根据聚类着色。

希望我没有错过论坛上这个问题的答案，如果确实如此，我深表歉意。任何帮助将不胜感激。

谢谢!

Answer 1

以下对 plotmatrix2 的轻微修改对我来说效果很好:

plotmatrix2 <- function (data, mapping = aes())
{
    grid <- expand.grid(x = 1:ncol(data), y = 1:ncol(data))
    grid <- subset(grid, x != y)
    all <- do.call("rbind", lapply(1:nrow(grid), function(i) {
        xcol <- grid[i, "x"]
        ycol <- grid[i, "y"]
        data.frame(xvar = names(data)[ycol], yvar = names(data)[xcol], 
            x = data[, xcol], y = data[, ycol], data)
    }))
    all$xvar <- factor(all$xvar, levels = names(data))
    all$yvar <- factor(all$yvar, levels = names(data))
    densities <- do.call("rbind", lapply(1:ncol(data), function(i) {
        data.frame(xvar = names(data)[i], yvar = names(data)[i], 
            x = data[, i])
    }))
    densities$xvar <- factor(densities$xvar, levels = names(data))
    densities$yvar <- factor(densities$yvar, levels = names(data))
    mapping <- defaults(mapping, aes_string(x = "x", y = "y"))
    class(mapping) <- "uneval"
    ggplot(all) + facet_grid(xvar ~ yvar, scales = "free") + 
        geom_point(mapping, na.rm = TRUE) + stat_density(aes(x = x, 
        y = ..scaled.. * diff(range(x)) + min(x)), data = densities, 
        position = "identity", colour = "grey20", geom = "line")
}


plotmatrix2(mtcars[,1:3],aes(colour = factor(cyl)))

这可能是一个ggplot2版本问题，但我不得不强制密度数据框中的分面变量成为因子(即使在GGally版本)。另外，通常不会将向量传递给 aes()，而只是传递列名称。