java - HTTP 请求以垃圾字符响应

Question

我正在尝试向网站发送请求以从中获取一些数据。但是，响应是垃圾字符，例如:

Ì 3ú¢¸<N¤@H±ü>§#Fe®¡+K·fÐcıaOqâò;'Êù!°â<rº\¼YDóß1K`òúüb¨ÑTcíÆ

这只发生在有数据的休息时，错误也可以正常工作。响应应该如下所示(来自浏览器请求):{"d":[{"__type":"CalendarTransport:http:...","activityId":2662,"activityImportIdentifier":null,"activityType":1,"allDay":false,"attendanceMode “:1，....

这是我的代码

        try
        {
            HttpsURLConnection httpsURLConnection;
            httpsURLConnection = (HttpsURLConnection) new URL("https", redacted, redacted).openConnection();

            try
            {
                httpsURLConnection.setRequestMethod("POST");
            }
            catch (Exception e)
            {
                Log.d(TAG, "doInBackground: oh no (3) it's a " + e.toString());
            }
            httpsURLConnection.setRequestProperty("Accept-Charset", "*/*");
            httpsURLConnection.setRequestProperty("Accept-Encoding", "gzip, deflate, br");
            httpsURLConnection.setRequestProperty("Connection", "keep-alive");
            httpsURLConnection.setRequestProperty("Content-Type", "application/json");
            httpsURLConnection.setRequestProperty("Cookie", new DomainCookies(redacted).toRequestHeader());
            httpsURLConnection.setDoOutput(true);
            httpsURLConnection.setDoInput(true);

            OutputStream os = httpsURLConnection.getOutputStream();

            OutputStreamWriter osw = new OutputStreamWriter(os, "UTF-8");
            osw.write(redacted);
            osw.flush();
            osw.close();
            os.close(); 

            StringBuilder mssg = new StringBuilder();
            DataInputStream inputStream;

            int status = httpsURLConnection.getResponseCode();

            if (status != HttpsURLConnection.HTTP_OK)
            {
                inputStream = new DataInputStream(httpsURLConnection.getErrorStream());
                Log.d(TAG, "doInBackground: HTTP error");
            }
            else
            {
                inputStream = new DataInputStream(httpsURLConnection.getInputStream());
                Log.d(TAG, "doInBackground: HTTP OK");
            }
            try
            {
                for(int c = inputStream.read(); inputStream.available() != 0; c = inputStream.read())
                {
                    mssg.append((char)c);
                }

                Log.d(TAG, "doInBackground: " + mssg);
            }
            catch (Exception e)
            {
                Log.d(TAG, "doInBackground: oh no (1) it's a " + e.toString());
            }
        }
        catch (MalformedURLException e)
        {
            Log.d(TAG, "onCreate: Oh no it's a " + e.toString());

        }
        catch (Exception e)
        {
            Log.d(TAG, "doInBackground: Oh no it's a " + e.toString());
        }

浏览器可以很好地得到响应，这一定是我正在做的事情(或者android，但我对此表示怀疑)

Answer 1

我首先要去掉这一行:

httpsURLConnection.setRequestProperty("Accept-Encoding", "gzip, deflate, br");

您的代码不处理这些形式的数据编码，因此不要要求服务器以这种方式对数据进行编码。

除此之外...现在是 2018 年了。停止使用 HttpsURLConnection。使用更现代且不易出错的内容，例如 OkHttp .