java - 用Gson反序列化Json，在TextViews中显示信息

Question

我几天来一直在尝试使用 GSON 反序列化这样的 JSON。

 {
"upcoming": [
    "silver",
    "gold",
    "silver",
    "silver",
    "silver",
    "silver",
    "gold",
    "silver",
    "silver"
],
"superMagical": 559,
"magical": 19,
"legendary": 79,
"epic": 699,
"giant": 94
 }

你知道如何在不同的 TextView 中显示此信息吗？

我已经成功地反序列化其他更简单的 Json 并在 TextView 中显示它们的信息，但这一个让我头疼。

我的想法是创建一个名为 Chests 的类，代码如下:

public class chests implements Serializable {


public int superMagical;
public int magical;
public int legendary;
public int epic;
public int giant;
}

然后，在另一个类中，我会执行以下操作

public class ClashChest implements Serializable {

@SerializedName("")
@Expose
public chests chestData; //

List<Upcoming> upcoming;
}

最后在我想要显示信息的 Activity 中我会这样做

public class ChestActivity extends AppCompatActivity {

public ClashChest datachest;
public TextView chest1, chest2, chest3, chest4;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_chest);

    datachest = (ClashChest)getIntent().getSerializableExtra("cofres");

    chest1 = findViewById(R.id.chest1txt);
    chest2 = findViewById(R.id.chest2txt);
    chest3 = findViewById(R.id.chest3txt);
    chest4 = findViewById(R.id.chest4txt);

    chest1.setText("" + datachest.chestData.legendary);

}
}

为了在 Activity 之间传递信息，我有带有以下代码的按钮

 btnCofre.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            if (!inputUser.getText().toString().isEmpty()) {


                OkHttpClient client = new OkHttpClient();


                StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
                StrictMode.setThreadPolicy(policy);

                Request request = new Request.Builder()
                        .url("https://api.royaleapi.com/player/" + inputUser.getText().toString() + "/chests")
                        .get()
                        .addHeader("auth", "Whatever")
                        .build();


                try {

                    Response response = client.newCall(request).execute();
                    String json = response.body().string();



                    if (response.isSuccessful()) {


                        Gson gson = new Gson();

                        ClashChest clashChest = gson.fromJson(json, ClashChest.class);

                        Intent intent;
                        intent = new Intent(MainActivity.this, ChestActivity.class);
                        intent.putExtra("cofres", clashChest);
                        startActivity(intent);


                    } 




    });

Answer 1

我会说创建一个与您的对象匹配的类，然后让 GSON 进行反序列化。你有这个:

 {
"upcoming": [
    "silver",
    "gold",
    "silver",
    "silver",
    "silver",
    "silver",
    "gold",
    "silver",
    "silver"
],
"superMagical": 559,
"magical": 19,
"legendary": 79,
"epic": 699,
"giant": 94
 }

等效的类是:

public class Foo {
    List<String> upcoming;
    int superMagical;
    int magical;
    int legendary;
    int epic;
    int giant;

    // eventually other functions, getter/setter...
}

然后反序列化它:

Foo targetObject = new Gson().fromJson(yourJson, Foo.class);

最后你可以在 View 中显示它:

yourTextview.setText(String.valueOf(targetObject.yourField)) // for the integers
yourTextview.setText(String.join(",", targetObject.upcoming)); // displays all values from upcoming separated by a coma

对于字符串，您可能还想使用 ListView

编辑:根据我从您添加的代码中看到的情况，您的 ClashChest 类与您尝试解析的 json 不匹配。当转换为json时，你可以认为一个类将被表示为一个json对象。因此，一旦转换为 JSON，您的 ClashChest 类将如下所示:

public class ClashChest implements Serializable {

@SerializedName("")
@Expose
public chests chestData; //

List<Upcoming> upcoming;
}

将会

{
    "chestData": 
    {
        // all the fieds you have in your chests class
    },
    "upcoming": // an array that contains x upcoming objects
    [
        {
            // every field you have in your Upcoming class
        }
    ]
}

如果你想匹配你的json，你应该把所有东西放在一个地方。即将到来的数组仅包含字符串，而不包含对象，因此如果您想匹配您的对象，它将是这样的:

public class Chest implements Serializable {
    List<String> upcoming;
    int superMagical;
    int magical;
    int legendary;
    int epic;
    int giant;
}