c# - 从另一个脚本访问start()函数错误？

Question

我如何从另一个脚本访问start()函数，因为启动函数只能定义一次

这是包含start()的脚本-

using UnityEngine;
 using System.Collections;

public class MoverBolt : MonoBehaviour {
public PlayerControl obj ; 
public float speed ;
public Rigidbody rb;

  void Start(){
    rb = GetComponent<Rigidbody>();
    rb.velocity = transform.forward * speed;

 }
}

需要访问start()的脚本

using UnityEngine;
using System.Collections;
  [System.Serializable]
 public class Boundary{
public float xMax,xMin,zMax,zMin;
}
  public class PlayerControl : MonoBehaviour
 { 
  public Boundary boundary ; 
  public float velocity;
   public float tilt;
    MoverBolt obj = new MoverBolt();  
 /* I made an object but it seems you are not supposed to create an object of class which is inheritance of MonoBehaviour */

    void FixedUpdate()
{
    float moveHorizontal = Input.GetAxis ("Horizontal");
    float moveVertical = Input.GetAxis ("Vertical");
    Vector3 movement = new Vector3 (moveHorizontal, 0.0f, moveVertical);
    obj.rb.velocity = movement*velocity;
    Vector3 current_position = obj.rb.position;
    obj.rb.position = new Vector3 ( Mathf.Clamp(current_position.x,boundary.xMin,boundary.xMax),
                                       0.0f,
                               Mathf.Clamp(current_position.z, boundary.zMin, boundary.zMax)
                                       );
    obj.rb.rotation= Quaternion.Euler(0.0f,0.0f,obj.rb.velocity.x*-tilt );
   }

 }

Error You are trying to create a MonoBehaviour using the 'new' keyword. This is not allowed. MonoBehaviours can only be added using AddComponent().

还有其他选择吗？

Answer 1

可以从外部调用Start()方法。只是公开。

public class MoverBolt : MonoBehaviour {
    public void Start () 
    {
        Debug.Log("MoverBolt.Start() was called");
    }
}

public class PlayerControl : MonoBehaviour {
    [SerializeField]
    private MoverBolt _moverBolt;

    void Start () 
    {
        _moverBolt.Start();
    }
}

控制台的输出是

MoverBolt.Start() was called
MoverBolt.Start() was called

更新1

我不建议这样做，因为Start()方法由您的代码和游戏引擎再次调用。

当我需要确保MonoBehaviour的设置正确时，在另一个类使用它之前。我将Awake/Start方法替换为 public void Initialize()方法，并从外部调用它。