xcode - Xcode 8.1 swift 3永远需要编译此代码

Question

我在以前使用swift 2.3的项目中有此类。当我将项目迁移到Swift 3时，xcode花费了很多时间进行编译，而我发现它停留在此类中。由于此类，我无法构建整个项目。有没有一种方法可以修改此类，以便可以构建项目，因此Xcode花费了很多时间来编译这段代码。如果我从MyClass中删除了几个属性，Xcode将迅速重新编译。有人对如何解决这个问题有任何想法吗？

import Foundation

class MyClass: NSObject {

    var id: String = ""
    var uid: String = ""
    var uname: String = ""
    var fname: String = ""
    var txt: String = ""
    var hay: Float = 0
    var flag = false
    var long: Double = 0
    var lat: Double = 0
    var altitude: Double = 0
    var course: Double = 0
    var speed: Double = 0
    var lname: String = ""
    var city: String = ""
    var country: String = ""
    var sublocal: String = ""
    var subarea: String = ""
    var thumb: String = ""
    var trash = false
    var date: Double = 0
    var updated: Double = 0
    var furl: String = ""

    func toAnyObject() -> Any {
        return [
            "id": id,
            "uid": uid,
            "uname": uname,
            "fname": fname,
            "txt": txt,
            "hay": hay,
            "flag": flag,
            "long": long,
            "lat": lat,
            "altitude": altitude,
            "course": course,
            "speed": speed,
            "lname": lname,
            "city": city,
            "country": country,
            "sublocal": sublocal,
            "trash": trash,
            "subarea": subarea,
            "thumb": thumb,
            "date": date,
            "updated": updated,
            "furl": furl
        ]
    }
}

Answer 1

不用大词典字面量重写。所以:

func toAnyObject() -> Any {
    var d = [String:Any]()
    d["id"] = id
    d["uid"] = uid
    // ... and so on ...
    return d
}