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java - 程序跳过 'if' 语句并默认为 'else'

转载 作者:行者123 更新时间:2023-12-02 10:43:28 25 4
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我正在为我的编程课做作业,但我的代码(再次)出了问题,我花了一个半小时尝试调试它。该代码是一种赌博游戏,用户输入下注金额,然后选择高、低或七。高是当骰子掷出 8 或更高时,低是当骰子掷出 6 或更低时,7 是当骰子掷出总共 7 时。如果骰子掷出 7,则赌注乘以 4 并奖励给用户。否则,当用户“输”时,他们就会输掉下注的金额。我似乎无法弄清楚到底出了什么问题。

首先,奖金不正确。他们在控制台中显示为“您赢得了 128 美元!”然后当代码重复时,当前池总是变成 132,即使用户输了并且钱应该被减去。此外,程序会跳过确定获胜方法中的“if”语句 - 即使用户应该获胜,它也会默认为 else。这将在 20 分钟内到期,但我不知道如何解决它!真诚感谢任何帮助!

package example;
import java.util.Scanner;

public class test
{

public static void main(String[] args)
{

Scanner inScanner = new Scanner(System.in);
int currentPool = 100;
int bet = ' ';
char highLow = ' ';
int roll = ' ';
int winnings = ' ';

System.out.println("You have " + currentPool + " dollars.");
getBet(inScanner, currentPool);
getHighLow(inScanner);
determineWinnings(highLow, bet, roll);
currentPool = currentPool + winnings;
System.out.println("");

while (bet != 0)
{
System.out.println("You have " + currentPool + " dollars.");
getBet(inScanner, currentPool);
getHighLow(inScanner);
determineWinnings(highLow, bet, roll);
currentPool = currentPool + winnings;
System.out.println("");
}


}



private static int getBet(Scanner inScanner, int currentPool)
{
System.out.print("Enter an amount to bet (0 to quit): ");
String strBet = inScanner.nextLine();
int bet = Integer.parseInt(strBet);


while (bet < 0 || bet > currentPool)
{
System.out.print("Your bet MUST be between 0 and " + currentPool + " dollars.");
System.out.println("You have " + currentPool + " dollars.");
System.out.print("Enter an amount to bet (0 to quit): ");
strBet = (inScanner.nextLine());
bet = Integer.parseInt(strBet);
}

if (bet == 0)
{
System.out.println("You have " + currentPool + " dollars.");
System.out.println("Goodbye!");
return bet;
}
else
{
return bet;
}
}


private static char getHighLow(Scanner inScanner)
{
System.out.print("High, Low, or Sevens (H/L/S): ");
String hls = inScanner.nextLine();
char highLow = ' ';

if (hls.equals("H") || hls.equals("h"))
{
highLow = 'H';
}
else if (hls.equals("L") || hls.equals("l"))
{
highLow = 'L';
}
else if (hls.equals("S") || hls.equals("s"))
{
highLow = 'S';
}
else
{
System.out.print("ERROR: invalid character entered. Please try again.");

while (!hls.equals("H") || !hls.equals("h") || !hls.equals("L") || !hls.equals("l") || !hls.equals("S") || !hls.equals("s"))
{
System.out.println("High, Low, or Sevens (H/L/S): ");
hls = inScanner.nextLine();
}
}
return highLow;
}


private static int getRoll()
{
int roll = (int)Math.floor(Math.random() * 6 + 1);
return roll;
}


private static int determineWinnings(char highLow, int bet, int roll)
{
int rollOne = getRoll();
int rollTwo = getRoll();
int total = rollOne + rollTwo;
int winnings = bet + 0;
System.out.println("Die 1 rolls: " + rollOne);
System.out.println("Die 2 rolls: " + rollTwo);
System.out.println("Total of two dice is: " + total);

if (highLow == 'H')
{
if (total >= 8)
{
System.out.println("You won " + winnings + " dollars!");

}
else
{
System.out.println("You lost!");
winnings = 0 - bet;

}
}
else if (highLow == 'L')
{
if (total <= 6)
{
System.out.println("You won " + winnings + " dollars!");

}
else
{
System.out.println("You lost!");
winnings = (0 - bet);

}
}
else
{
if (total == 7)
{
winnings = bet * 4;
System.out.println("You won " + winnings + " dollars!");

}
else
{
System.out.println("You lost!");
winnings = 0 - bet;

}
}
return winnings;
}

}

最佳答案

您没有理解的部分是每个方法 - 事实上,对每个方法的每次调用 - 都有自己的局部变量集合。这意味着

  • main 中声明的 winnings 变量与在 defineWinnings 中声明的 winnings 变量不同;
  • main 中声明的 bet 变量与在 getBet 中声明的 bet 变量不同。

您需要做的是确保将每个调用的方法返回的值分配给调用者中您想要存储它的变量方法。因此,在 main 中,当您调用 getBet 时,您实际上想要编写

bet = getBet(inScanner, currentPool);

以便将 getBet 返回的值分配给 main 中的 bet 变量。同样,当你调用defineWinnings时,你需要写

winnings = determineWinnings(highLow, bet, roll);

这样,从 defineWinnings 返回的值就会被分配给 main 中的 winnings 变量。

如果您不这样做,则 main 中的所有变量都将保留其原始值,对于 currentPool10032 代表奖金(因为 ' ' 只是 32 的另一种书写方式)。这就是为什么您的最终值是 132

关于java - 程序跳过 'if' 语句并默认为 'else',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52767059/

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