java - Spring Data JPA @Query 注解的问题(SQL 语法错误)

Question

编辑:我想检查某个用户是否在组中拥有权限。如果有更好的解决方案而不查询他的所有权限请告诉我。

以下查询给了我一个我无法理解的错误:

@Repository
public interface PrivilegeRepository extends JpaRepository<Privilege, Long> {

    @Query("select p from Privilege p " +
            "inner join p.userTypes " +
            "inner join UserGroup u " +
            "where u.user.id=:uid and u.group.id=:gid")
    List<Privilege> getPrivilegesOfUser(@Param("uid") Long uid, @Param("gid") Long gid);

}

错误:

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where usergroup1_.user_id=28 and usergroup1_.group_id=18' at line 1
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) ~[na:1.8.0_144]
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62) ~[na:1.8.0_144]
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45) ~[na:1.8.0_144]
    at java.lang.reflect.Constructor.newInstance(Constructor.java:423) ~[na:1.8.0_144]

用户组实体

@Entity
@Table(name = "user_to_group")
public class UserGroup {

    @EmbeddedId
    private UserGroupId id;

    @ManyToOne(fetch = FetchType.LAZY,
            cascade = {CascadeType.DETACH, CascadeType.MERGE,
                    CascadeType.REFRESH, CascadeType.PERSIST})
    @MapsId("userId")
    @JoinColumn(name = "user_id", insertable = false, updatable = false)
    private User user;

    @ManyToOne(fetch = FetchType.LAZY,
            cascade = {CascadeType.DETACH, CascadeType.MERGE,
                    CascadeType.REFRESH, CascadeType.PERSIST})
    @MapsId("groupId")
    @JoinColumn(name = "group_id", insertable = false, updatable = false)
    private Group group;

    @ManyToOne(fetch = FetchType.LAZY,
            cascade = {CascadeType.DETACH, CascadeType.MERGE,
                    CascadeType.REFRESH, CascadeType.PERSIST})
    @JoinColumn(name = "user_type_id")
    private UserType userType;

    @Column(name = "is_blocked",
    insertable = false)
    private boolean isBlocked = false;

我首先在 MYSQL Workbench 中尝试了等效查询，并且工作得很好。 Jpa 存储库实现没有任何内容。这是在 MYSQL 上运行的代码:

select p.name from privilege p 
    inner join user_type_to_privilege utp 
        on p.id=utp.privilege_id
    natural join user_to_group utg
    where utg.user_id=16 and
        utg.group_id=9;

这是我使用的方言:spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQLDialect这是过时的还是什么？

Answer 1

问题出在第二个内部联接上。它不明确，不知道要匹配哪一列来进行连接。有效的查询:

@Query("select p from Privilege p " +
            "inner join p.userTypes t " +
            "inner join UserGroup u on t.id=u.userType.id "+
            "where u.user.id=:uid and u.group.id=:gid")
    List<Privilege> getPrivilegesOfUser(@Param("uid") Long uid, @Param("gid") Long gid);