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java - Spring Security - 存储库 SocialUser

转载 作者:行者123 更新时间:2023-12-02 10:39:20 25 4
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我的问题是使用 facebook 登录我的网络应用程序。正常的登录/注册工作正常,但当它来自社​​交提供商时,我遇到了问题,以下是我的重要文件和其他文件:

SecurityConfig.java

package pl.java.learning.todolist.infrastructure.config;

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {

@Autowired
private MyUserDetailsService userDetailsService;

@Autowired
private DataSource dataSource;

@Autowired
private UserSocialService userSocialService;

@Override
protected void configure(final AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(authenticationProvider());
}

@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth)
throws Exception {
auth
.jdbcAuthentication()
.dataSource(dataSource)
.withDefaultSchema();
}

@Bean
public DaoAuthenticationProvider authenticationProvider() {
DaoAuthenticationProvider authProvider = new DaoAuthenticationProvider();
authProvider.setUserDetailsService(userDetailsService);
authProvider.setPasswordEncoder(encoder());
return authProvider;
}

@Bean
public PasswordEncoder encoder() {
return new BCryptPasswordEncoder(11);
}

@Override
protected MyUserDetailsService userDetailsService() {
return userDetailsService;
}

@Bean
public SimpleSocialUserDetailsService simpleSocialUserDetailsService() {
return new SimpleSocialUserDetailsService(userDetailsService, userSocialService);
}

@Override
protected void configure(final HttpSecurity http) throws Exception {
http
.csrf().disable()
.headers().frameOptions().disable()
.and()
.authorizeRequests()
.antMatchers("/login*", "/success*").anonymous()
.antMatchers("/auth/**", "/signup/**", "/css/*", "/webjars/**","/js/*","/image/*").permitAll()
.anyRequest().authenticated()
.and()
.formLogin().loginPage("/login")
.successForwardUrl("/tasks")
.and()
.logout()
.logoutUrl("/logout")
.logoutSuccessUrl("/logout-success").permitAll()
.and()
.apply(new SpringSocialConfigurer());
}
}

SocialConfig.java

package pl.java.learning.todolist.infrastructure.config;

@Configuration
@EnableSocial
public class SocialConfig implements SocialConfigurer {

@Autowired
private DataSource dataSource;

@Bean
public ConnectController connectController(
ConnectionFactoryLocator connectionFactoryLocator,
ConnectionRepository connectionRepository) {
return new ConnectController(connectionFactoryLocator, connectionRepository);
}

@Override
public void addConnectionFactories(ConnectionFactoryConfigurer connectionFactoryConfigurer,
Environment env) {
connectionFactoryConfigurer.addConnectionFactory(new FacebookConnectionFactory(
env.getProperty("spring.social.facebook.app-id"),
env.getProperty("spring.social.facebook.app-secret")
));
}

@Override
public UserIdSource getUserIdSource() {
return new AuthenticationNameUserIdSource();
}

@Override
public UsersConnectionRepository getUsersConnectionRepository(
ConnectionFactoryLocator connectionFactoryLocator) {
JdbcUsersConnectionRepository repository =
new JdbcUsersConnectionRepository(
dataSource,
connectionFactoryLocator,
Encryptors.noOpText());
repository.setConnectionSignUp(
new SecurityImplicitConnectionSignUp(userDetailsManager()));
return repository;
}

@Bean
public JdbcUserDetailsManager userDetailsManager() {
JdbcUserDetailsManager manager = new JdbcUserDetailsManager();
manager.setDataSource(dataSource);
manager.setEnableAuthorities(true);
return manager;
}
}

CustomSocialUser.java

package pl.java.learning.todolist.domain.social;

import java.util.Collection;
import java.util.List;
import javax.persistence.Entity;
import javax.persistence.Table;
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.EqualsAndHashCode;
import lombok.NoArgsConstructor;
import lombok.ToString;
import org.springframework.security.core.GrantedAuthority;
import pl.java.learning.todolist.infrastructure.persistence.BaseEntity;

@Data
@Entity
@AllArgsConstructor
@NoArgsConstructor
@EqualsAndHashCode(callSuper = true)
@ToString
@Table(name = "users")
public class CustomSocialUser extends BaseEntity {
private String username;
private String password;
private Collection<? extends GrantedAuthority> authorities;
}

SimpleSocialUserDetailsS​​ervice.java

@Service
@RequiredArgsConstructor
public class SimpleSocialUserDetailsService implements SocialUserDetailsService {

private final UserDetailsService userDetailsService;
private final UserSocialService userSocialService;

@Override
public SocialUserDetails loadUserByUserId(String userId)
throws UsernameNotFoundException, DataAccessException {
CustomSocialUser customSocialUser = userSocialService.findByUsername(userId);
return new SocialUser(
customSocialUser.getUsername(),
customSocialUser.getPassword(),
customSocialUser.getAuthorities());
}
}

MyUserDetailsS​​ervice.java

@Service
@RequiredArgsConstructor
public class MyUserDetailsService implements UserDetailsService {

private final UserRepository userRepository;

@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
User user = userRepository.findByLogin(username);
if(user == null) {
throw new UsernameNotFoundException(username);
}
return new MyUserPrincipal(user);
}
}

SecurityImplicitConnectionSignUp.java

@RequiredArgsConstructor
public class SecurityImplicitConnectionSignUp implements ConnectionSignUp {

public final UserDetailsManager userDetailsManager;

@Override
public String execute(Connection<?> connection) {
String providerUserId = connection.getKey().getProviderUserId();
User newUser = new User(providerUserId,
"",
Arrays.asList(new SimpleGrantedAuthority("USER")));
userDetailsManager.createUser(newUser);
return providerUserId;
}
}

UserSocialRepository.java

public interface UserSocialRepository extends JpaRepository<CustomSocialUser, Long> {
@Query("SELECT u FROM Users u WHERE u.username = ?1")
CustomSocialUser findByUsername(String username);
}

MyUserPrincipal.java

@RequiredArgsConstructor
public class MyUserPrincipal implements UserDetails {

private final User user;

@Override
public Collection<? extends GrantedAuthority> getAuthorities() {
return user.getRoles();
}

public Long getUserId() {
return user.getId();
}

@Override
public String getPassword() {
return user.getPassword();
}

@Override
public String getUsername() {
return user.getLogin();
}

@Override
public boolean isAccountNonExpired() {
return true;
}

@Override
public boolean isAccountNonLocked() {
return true;
}

@Override
public boolean isCredentialsNonExpired() {
return true;
}

@Override
public boolean isEnabled() {
return user.getEnabled();
}
}

我遇到这样的错误:

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.Collection, at table: users, for columns: [org.hibernate.mapping.Column(authorities)]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1699)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:573)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:495)
at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:317)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:315)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:199)
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1089)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:859)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:550)
at org.springframework.boot.web.servlet.context.ServletWebServerApplicationContext.refresh(ServletWebServerApplicationContext.java:140)
at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:762)
at org.springframework.boot.SpringApplication.refreshContext(SpringApplication.java:398)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:330)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1258)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1246)
at pl.java.learning.todolist.TodoListApplication.main(TodoListApplication.java:10)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.springframework.boot.devtools.restart.RestartLauncher.run(RestartLauncher.java:49)
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.Collection, at table: users, for columns: [org.hibernate.mapping.Column(authorities)]
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:402)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:377)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.afterPropertiesSet(LocalContainerEntityManagerFactoryBean.java:341)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1758)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1695)
... 21 common frames omitted
Caused by: org.hibernate.MappingException: Could not determine type for: java.util.Collection, at table: users, for columns: [org.hibernate.mapping.Column(authorities)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:456)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:423)
at org.hibernate.mapping.Property.isValid(Property.java:226)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:597)
at org.hibernate.mapping.RootClass.validate(RootClass.java:265)
at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:329)
at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:461)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:892)
at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:57)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:365)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:390)
... 25 common frames omitted

最佳答案

问题出在您的存储库中:

@Repository
public interface UserSocialRepository extends JpaRepository<SocialUser, Long> {
@Query("SELECT u FROM Users u WHERE u.username = ?1")
SocialUser findByUsername(String username);
}

1) 如果您使用 Spring Data 并且您的类是从 JpaRepository 扩展的,则不必在您的类上添加 @Repository 注解。

2)在你的方法中

SocialUser findByUsername(String username);

您返回SocialUser,它是Spring Social模块中的一个类,并且该类不是由JPA管理的(这就是您收到错误的原因)。您应该使用实体或 Spring Data 投影作为存储库方法中的返回类型。

假设您有 Users 实体,应该类似于:

@Entity
@Table(name = "users")
public class Users {
private String username;
// ...
}

您可以按以下方式重写您的方法:

Users findByUsername(String username);

然后您可以将实体/投影转换为服务中的 SocialUser:

public UserDetails findByUsername(String username) {
Users user = userSocialRepository.findByUsername(username);
return new SocialUser(user.getUsername(), ...);
}

关于java - Spring Security - 存储库 SocialUser,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53045225/

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