c++ - 大多数代码不只显示欢迎消息和 “enter pin”吗？

Question

分配:

输入错误的数字位数(3或5位数字的密码)时a
消息应显示“您输入的密码不正确!!
必须输入四位数的密码。”

通过显示以前显示的消息，程序应
允许您重新输入正确的数字位数。

尝试次数应为3次。

输入正确的数字后，将显示一条消息
“您的密码已被接受!”

每次输入任意数量的密码时，密码都必须以星号显示。

码:

#include <conio.h>

#include <iostream>
//#include <cstdlib.h>
#include <cmath>

using namespace std;

int main() {
  string pass = "";
  int attempts = 3;

  cout << "^^^^^^^^^^^^^^^^^^^^^^^^^^^" << endl;
  cout << "< Welcome to The Bank     >" << endl;
  cout << "<                         >" << endl;
  cout << "< Please Enter Pin Below  >" << endl;
  cout << " ^^^^^^^^^^^^^^^^^^^^^^^^^^" << endl;

  cout << "\nEnter Pin Number: " << endl;
  cin >> pass;

  // attempts= getch();
  while (attempts <= 3) {
    cout << "*";
    getch();
    attempts++;  // take this out and it display to infinity
                 // }

    if (pass == "1718") {
      cout << " lOGIN  IN..." << endl << endl;
      attempts = -1;
    }

    else {
      cout << "\nWRONT PIN-TRY AGAIN: " << endl << endl;
      attempts--;
      cout << " REMAINING ATTEMPTS: " << attempts << endl << endl;
    }

    if (attempts == 0) {
      cout << "Exceed the Pin attempts. Try Later. " << endl << endl;
    }

    if (attempts == -1) {
      cout << "********************************" << endl;
      cout << "*  Welcome to Magali's Bank    *\n";
      cout << "*  Select Option:              *\n";
      cout << "*    1. Check Balance          *\n";
      cout << "*    2. Withdraw               *\n";
      cout << "*    3. Deposit                *\n";
      cout << "*    4. Exit                   *\n";
      cout << "********************************\n";

      int balance = 500;
      float withdraw;
      float deposit;
      int user;

      cout << "Enter Number: ";
      cin >> user;

      while (user != 4) {
        switch (user) {
          case 1:
            cout << " Your balance is: " << balance << endl;
            break;

          case 2:
            cout << "Enter the amount you want withdraw: ";
            cin >> withdraw;
            balance = balance - withdraw;
            break;

          case 3:
            cout << "Enter the amount you want to deposit: ";
            cin >> deposit;
            balance = balance + deposit;
            break;

          default:
            cout << " Need to type 1 for Balance, 2 to Withdraw, 3 to Deposit "
                    "and 4 to Exit. ";
        }
        cout << "Enter Number: ";
        cin >> user;
      }
      cout << "\nTHANKS FOR USING THE SYSTEM!\n";
    }
  }
  return 0;
}

Answer 1

您的代码效率低下，但您却要求这样做。我只调试其中的一部分，您需要输入和显示错误。

string pass="";
int attempts=3;
const string pin = "1718";
//DO whatever you want 
//while loop to take input

while (attempts >0)
     {
         cout << "\nEnter Pin Number: " << endl;
         cin >> pass;
         for(auto i : pass)
            cout<<"*";
         if(pass == pin){
            attempts = 3;
            cout<<"Your Pin has been accepted.\n";
            break;}
        else{
        cout <<"\nWRONT PIN-TRY AGAIN: " << endl << endl;
       attempts--;
       cout << " REMAINING ATTEMPTS: " << attempts << endl << endl;
        }
    }

if (attempts == 0)
 {
 cout << "Exceed the Pin attempts. Try Later. "<< endl << endl;
 cout<<"Your account has been locked for a day .\n";
 exit(0);
 }

如果您不了解任何部分，请注释掉。