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haskell - 如何在类型族中为使用类型相等的约束定义自定义类型错误?

转载 作者:行者123 更新时间:2023-12-02 10:37:56 26 4
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因此,我们可以像这样定义成员资格约束:

{-# LANGUAGE ConstraintKinds #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE PolyKinds #-}
{-# LANGUAGE TypeFamilies #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE GADTs #-}

module Whatever where

type family MemberB (x :: k) (l :: [k]) where
MemberB _ '[] = 'False
MemberB a (a : xs) = 'True
MemberB a (b : xs) = MemberB a xs

type Member x xs = MemberB x xs ~ 'True

data Configuration = A | B | C

data Action (configuration :: Configuration) where
Action1 :: Member cfg '[ 'A ] => Action cfg
Action2 :: Member cfg '[ 'B, 'C ] => Action cfg
Action3 :: Member cfg '[ 'A, 'C ] => Action cfg

exhaustive :: Action 'A -> ()
exhaustive Action1 = ()
exhaustive Action3 = ()
exhaustive Action2 = ()

但是我们收到的错误消息信息并不丰富:

 • Couldn't match type ‘'False’ with ‘'True’
Inaccessible code in
a pattern with constructor:
Action2 :: forall (cfg :: Configuration).
Member cfg '['B, 'C] =>
Action cfg,
in an equation for ‘exhaustive’
• In the pattern: Action2
In an equation for ‘exhaustive’: exhaustive Action2 = () (intero)

使用新的 TypeError 功能来改进此消息会很好,但是,一个简单的解决方案会吞噬该错误:

import GHC.TypeLits

type family MemberB (x :: k) (l :: [k]) where
MemberB _ '[] = TypeError ('Text "not a member")
MemberB a (a : xs) = 'True
MemberB a (b : xs) = MemberB a xs

看来,TypeError 的行为可能与任何类型相同,因此它可以与 'True 愉快地结合起来?

有没有办法在保留成员资格行为的同时获得良好的类型错误?

最佳答案

嗯,它不使用 TypeError,但您可能会发现它很有趣:

{-# LANGUAGE ConstraintKinds #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE PolyKinds #-}
{-# LANGUAGE TypeFamilies #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE GADTs #-}

module Whatever where

data IsMember k = IsMember | Isn'tMember k [k]

type family MemberB (x :: k) (l :: [k]) (orig :: [k]) where
MemberB a '[] ys = 'Isn'tMember a ys
MemberB a (a : xs) ys = 'IsMember
MemberB a (b : xs) ys = MemberB a xs ys

type Member x xs = MemberB x xs xs ~ 'IsMember

data Configuration = A | B | C

data Action (configuration :: Configuration) where
Action1 :: Member cfg '[ 'A ] => Action cfg
Action2 :: Member cfg '[ 'B, 'C ] => Action cfg
Action3 :: Member cfg '[ 'A, 'C ] => Action cfg

exhaustive :: Action 'A -> ()
exhaustive Action1 = ()
exhaustive Action3 = ()
exhaustive Action2 = ()

现在该错误信息更丰富了:

test.hs:32:16: error:
• Couldn't match type ‘'Isn'tMember 'A '['B, 'C]’ with ‘'IsMember’
Inaccessible code in
a pattern with constructor:
Action2 :: forall (cfg :: Configuration).
Member cfg '['B, 'C] =>
Action cfg,
in an equation for ‘exhaustive’
• In the pattern: Action2
In an equation for ‘exhaustive’: exhaustive Action2 = ()
|
32 | exhaustive Action2 = ()
| ^^^^^^^

关于haskell - 如何在类型族中为使用类型相等的约束定义自定义类型错误?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52730463/

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