c++ - 无法将QWidget扩展的实例添加到QVector

Question

我有一个Variable类，是QWidget的扩展。我想将其添加到QVector <Variable> *list_variables vector 中，但是当我尝试时，出现错误

Attempt to refer to a deleted function

这是代码:

QVector <Variable> *list_variables;
QVBoxLayout *layout = new QVBoxLayout (scroll_area);

for (int i = 0; i < 5; i ++)
{
    Variable *variable = new Variable;
    list_variables->append(*variable); // Error happens here
    layout->addWidget(variable);
}

Variable.h:

#ifndef VARIABLE_H
#define VARIABLE_H

#include "constant.h"

class Variable : public QWidget
{
    public :
        Variable();

    private :
        QLineEdit *line_edit_name, *line_edit_value, *line_edit_imprecision;
};

#endif // VARIABLE_H

Variable.cpp:

#include "constant.h"

Variable::Variable()
{
    this->setFixedSize(240, 30);

    line_edit_name = new QLineEdit(this);
    line_edit_name->setGeometry(0, 0, 50, 20);
    line_edit_name->setPlaceholderText("Name");

    line_edit_value = new QLineEdit (this);
    line_edit_value->setGeometry(60, 0, 80, 20);
    line_edit_value->setPlaceholderText("Value");

    line_edit_imprecision = new QLineEdit (this);
    line_edit_imprecision->setGeometry(150, 0, 80, 20);
    line_edit_imprecision->setPlaceholderText("Imprecision");
}

所有包含内容都在“constant.h”中完成

Answer 1

我找到了一个解决方案:将QVector声明为Variable指针的 vector 。

所以我有:

QVector <Variable*> list_variables; // Instead of QVector <Variable> *list_variables;
QVBoxLayout *layout = new QVBoxLayout (scroll_area);

for (int i = 0; i < 5; i ++)
{
    Variable *variable = new Variable;
    list_variables.append(variable); // Instead of list_variables->append(*variable);
    layout->addWidget(variable);
}