java - 从 JSON 响应中提取值

Question

从休息服务中我收到以下 json 响应

{"code":1,"message":"success","status":"success","users":[{"email":"qqq@aa.aa","name":"qq"},{"email":"dd@dd.dd","name":"dd"},{"email":"cc@vv.vv","name":"cc"},{"email":"qq@qq.qq","name":"qq"},{"email":"qq@qq.qq","name":"qq"}]}

当我尝试将其转换为 JSONObject 时，它抛出一个错误，这就是我尝试提取 JSON 响应的方法，

jsonObject = new JSONObject(response.body().string());

上面的脚本引发了错误。错误如下，

E/AndroidRuntime: FATAL EXCEPTION: OkHttp Dispatcher
Process: com.example.ej.ziphiotest, PID: 21945
java.lang.IllegalStateException: closed
    at okio.RealBufferedSource.rangeEquals(RealBufferedSource.java:408)
    at okio.RealBufferedSource.rangeEquals(RealBufferedSource.java:402)
    at okhttp3.internal.Util.bomAwareCharset(Util.java:432)
    at okhttp3.ResponseBody.string(ResponseBody.java:174)
    at com.example.ej.ziphiotest.requests.UserRequest$1.onResponse(UserRequest.java:85)
    at okhttp3.RealCall$AsyncCall.execute(RealCall.java:153)
    at okhttp3.internal.NamedRunnable.run(NamedRunnable.java:32)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
    at java.lang.Thread.run(Thread.java:818)

编辑:

这是请求:

final Request request = new Request.Builder()
            .header("key", params[0])
            .url(URL)
            .build();

    try {
        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {
                call.cancel();
            }

            @Override
            public void onResponse(Call call, Response response) throws IOException {
                if (response.code() == 200){
                    try {
                        jsonObject = new JSONObject(response.body().string());
                        restResponse = new RestResponse(jsonObject.getString("status"), jsonObject.getString("code"), jsonObject.getString("message"), null, jsonObject.getJSONArray("users"));
                        onTaskComplete.onTaskComplete(restResponse);
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }

            }
        });
    } catch (Exception e) {
        e.printStackTrace();
    }


}

我错过的地方。感谢您抽出宝贵的时间

Answer 1

问题是我在很短的时间内使用了 response.body().string() 两次。作为@Firoz Memon在评论中说。

Try storing it in a variable and then using the variable, not the response.body().string() code. Because response body can be huge so OkHttp doesn’t store it in memory, it reads it as a stream from network when you need it. When you read body as a string() OkHttp downloads response body and returns it to you without keeping reference to the string, it can’t be downloaded twice without new request.

复制自@Firoz Memon上面的评论。

原始引用:https://github.com/square/okhttp/issues/1240