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java - 如何避免java.lang.StackOverflowError?

转载 作者:行者123 更新时间:2023-12-02 10:35:10 24 4
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我在我的绘画应用程序中实现了洪水填充算法。我的代码在该算法上没有问题。

当我测试程序时,我注意到洪水填充对于小的封闭区域工作正常,但是当洪水填充应用于大区域时,我得到了 java.lang.StackOverflowError 并且大区域在重新绘制后被填充了一半。我知道 Java 对于递归方法的调用堆栈有限,我不确定如何优化我的代码来解决这个问题,是否需要调整我的缓冲图像的大小?

代码:

import java.awt.*;

import java.awt.event.*;

import java.awt.image.BufferedImage;

import javax.swing.*;

public class MinimumVerifiableExample extends JFrame {
private static final long serialVersionUID = 1L;

private final int WIDTH = 800;
private final int HEIGHT = 600;

private PaintPanel panel;
private JButton button;

private MinimumVerifiableExample() {
super("Paint App Plus");

panel = new PaintPanel();
button = new JButton("Fill with mouse click");

button.addActionListener(e -> {
panel.setFloodFill(Color.RED);
});

setSize(WIDTH, HEIGHT);
setLocationRelativeTo(null);

setLayout(new BorderLayout());

add(panel, BorderLayout.CENTER);
add(button, BorderLayout.SOUTH);

setResizable(false);
}

public static void main(String[] args) {
EventQueue.invokeLater(() -> {
MinimumVerifiableExample frame = new MinimumVerifiableExample();
frame.setVisible(true);
});
}

private class PaintPanel extends JComponent implements MouseListener, MouseMotionListener {
private static final long serialVersionUID = 1L;

private final int canvasWidth = 784;
private final int canvasHeight = 526;

private BufferedImage canvas;
private boolean floodFill;
private Color fillColour;

private boolean painting;
private int prevX;
private int prevY;
private int curX;
private int curY;

private PaintPanel() {
canvas = new BufferedImage(canvasWidth, canvasHeight, BufferedImage.TYPE_INT_RGB);
floodFill = false;
fillColour = null;

painting = false;

Graphics2D paintBrush = canvas.createGraphics();

paintBrush.setColor(Color.WHITE);
paintBrush.fillRect(0, 0, canvas.getWidth(), canvas.getHeight());
paintBrush.dispose();

addMouseListener(this);
addMouseMotionListener(this);
}

protected void paintComponent(Graphics g) {
super.paintComponent(g);
g.setColor(Color.WHITE);
g.fillRect(0, 0, canvas.getWidth(), canvas.getHeight());
g.drawImage(canvas, getInsets().left, getInsets().top, canvasWidth, canvasHeight, this);
}

public void setFloodFill(Color fillColour) {
floodFill = true;
this.fillColour = fillColour;
}

private void floodFill(int x, int y, Color target, Color previous) {
if (x > canvas.getWidth() || x < 1 || y > canvas.getHeight() || y < 1)
return;

if (canvas.getRGB(x, y) != previous.getRGB())
return;

previous = new Color(canvas.getRGB(x, y));
canvas.setRGB(x, y, target.getRGB());

floodFill(x + 1, y, target, previous);
floodFill(x, y + 1, target, previous);
floodFill(x - 1, y, target, previous);
floodFill(x, y - 1, target, previous);
}

private void updateBoard() {
Graphics2D paintBrush = canvas.createGraphics();
paintBrush.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
paintBrush.setPaint(Color.BLACK);

paintBrush.setStroke(new BasicStroke(10, BasicStroke.CAP_ROUND, BasicStroke.JOIN_ROUND));
paintBrush.drawLine(prevX, prevY, curX, curY);

paintBrush.dispose();
}

public void mousePressed(MouseEvent e) {
if (floodFill) {
floodFill(e.getX(), e.getY(), fillColour, new Color(canvas.getRGB(e.getX(), e.getY())));
repaint();

floodFill = false;
return;
}

if (painting) return;

prevX = e.getX();
prevY = e.getY();

painting = true;
}

public void mouseReleased(MouseEvent e) {
if (!painting) return;

curX = e.getX();
curY = e.getY();

painting = false;
}

public void mouseDragged(MouseEvent e) {
curX = e.getX();
curY = e.getY();

if (!painting) return;

updateBoard();
repaint();

prevX = curX;
prevY = curY;
}

public void mouseClicked(MouseEvent e) {}
public void mouseEntered(MouseEvent e) {}
public void mouseExited(MouseEvent e) {}
public void mouseMoved(MouseEvent e) {}
}
}

最佳答案

解决方案:

    private class StackItem {
private final int x;
private final int y;
private final Color previous;

public StackItem(int x, int y, Color previous) {
this.x = x;
this.y = y;
this.previous = previous;
}
}

private void floodFill(final int initialX, final int initialY, final Color target, final Color previous) {
Stack<StackItem> stack = new Stack<>();
stack.push(new StackItem(initialX, initialY, previous));

while (!stack.isEmpty()) {
StackItem stackItem = stack.pop();
if (stackItem.x > canvas.getWidth() || stackItem.x < 1 || stackItem.y > canvas.getHeight() || stackItem.y < 1)
continue;

if (canvas.getRGB(stackItem.x, stackItem.y) != stackItem.previous.getRGB())
continue;

Color previousColor = new Color(canvas.getRGB(stackItem.x, stackItem.y));
canvas.setRGB(stackItem.x, stackItem.y, target.getRGB());

stack.push(new StackItem(stackItem.x + 1, stackItem.y, previousColor));
stack.push(new StackItem(stackItem.x, stackItem.y + 1, previousColor));
stack.push(new StackItem(stackItem.x - 1, stackItem.y, previousColor));
stack.push(new StackItem(stackItem.x, stackItem.y - 1, previousColor));

}


}

请原谅使用继续。我想保持原始解决方案的结构与此类似。但我建议不要使用它。

正如您所看到的,这是将递归转换为循环的直接方法。我们不使用大小有限的 JVM 堆栈,而是使用使用 JVM 堆的集合。

Class StackItem 只是递归函数所有参数的表示。参数 target 不会更改,因此它不是其中的一部分。每次递归调用都等于将新参数推送到我们的 Stack 结构中。每次调用“递归”函数都等于从顶部弹出参数并使用该参数执行逻辑。

关于java - 如何避免java.lang.StackOverflowError?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53348957/

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