java - 如何使此代码打印数组中的最高值？

Question

这个问题已经有答案了:

How to find array index of largest value? (9 个回答)

已关闭 4 年前。

如何使此代码打印数组中的最高值？

示例(view detailled screenshot):

• 玩家 1 得分 = 1
• 玩家 2 得分 = 2

• 玩家 3 得分 = 1

  Player 2 is the winner.

• 玩家 1 得分 = 1

• 玩家 2 得分 = 3

• 玩家 3 得分 = 3

  Player 2 is the winner.
  Player 3 is the winner.

• 玩家 1 得分 = 1

• 玩家 2 得分 = 1
• 玩家 3 得分 = 1

  Player 1 is the winner.
  Player 2 is the winner.
  Player 3 is the winner.`

到目前为止，这是我的代码尝试:

/**
 * [algorithm description here]
 * @param players
 * @param cards
 */
public static void playGame(int players, int cards) {
    if (players * cards > 52) {
        System.out.println("Not enough cards for that many players.");
        return;
    }
    boolean[] deck = new boolean[52];
    int[] playerScore = new int[players];
    for (int i = 0; i < players; i++) {
        System.out.println("Player " + (i + 1));
        int[] hand = Cards.dealHandFromDeck(cards, deck);
        Cards.printHand(hand);
        System.out.println("Score = " + Cards.pointValue(hand));
        System.out.println();
        playerScore[i] = Cards.pointValue(hand);
    }
    //go through playerScore array twice, first to find the highest score, then who has that score
}

Answer 1

迭代playerScore，将其值与上一次迭代之前的最大值进行比较，如果迭代为零，则将其与 0 进行比较。如果更大，则最大值为迭代值。

int maximumValue = 0;
for(int i = 0; i < playerScore.length; i++) {
    if(playerScore[i] > maximumValue) {
        maximumValue = playerScore[i];
    }
}

要检查具有最大值的播放器，您可以使用与之前相同的代码片段:

int maximumValue = 0;
long player = -1;
for(int i = 0; i < playerScore.length; i++) {
    if(playerScore[i] > maximumValue) {
        maximumValue = playerScore[i];
        player = i;
    }
}
if(player > -1) System.out.println("Player with highest score: " + (player + 1));