c++ - 使用yaml-cpp解析YAML文件

Question

我正在使用yaml-cpp 0.3.0(旧的API版本)来解析yaml文件(这是我从here获得的)。
这是yaml文件:

- name: Ogre
  position: [0, 5, 0]
  powers:
    - name: Club
      damage: 10
    - name: Fist
      damage: 8
- name: Dragon
  position: [1, 0, 10]
  powers:
    - name: Fire Breath
      damage: 25
    - name: Claws
      damage: 15
- name: Wizard
  position: [5, -3, 0]
  powers:
    - name: Acid Rain
      damage: 50
    - name: Staff
      damage: 3

现在，我尝试使用以下代码解析权力名称和损失:

#include "yaml-cpp/yaml.h"
#include <iostream>
#include <fstream>
#include <string>
#include <vector>

// our data types
struct Vec3 {
   float x, y, z;
};

struct Power {
   std::string name;
   int damage;
};

struct Monster {
   std::string name;
   Vec3 position;
   std::vector <Power> powers;
};

// now the extraction operators for these types
void operator >> (const YAML::Node& node, Vec3& v) {
   node[0] >> v.x;
   node[1] >> v.y;
   node[2] >> v.z;
}

void operator >> (const YAML::Node& node, Power& power) {
   node["name"] >> power.name;
   node["damage"] >> power.damage;
}

void operator >> (const YAML::Node& node, Monster& monster) {
   node["name"] >> monster.name;
   node["position"] >> monster.position;
   const YAML::Node& powers = node["powers"];
   for(unsigned i=0;i<powers.size();i++) {
      Power power;
      powers[i] >> power;
      monster.powers.push_back(power);
   }
}

int main()
{
   std::ifstream fin("robot.yaml");
   YAML::Parser parser(fin);
   YAML::Node doc;
   parser.GetNextDocument(doc);
   for(unsigned i=0;i<doc.size();i++) {
      Power power;
      doc[i] ["powers"] >> power;
      std::cout << power.name << "\n";
      std::cout << power.damage << "\n";
   }

   return 0;
}

看来我的代码显示这样的错误:

terminate called after throwing an instance of 'YAML::TypedKeyNotFound<std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >'
  what():  yaml-cpp: error at line 4, column 5: key not found: name
Aborted (core dumped)

请帮助我理解为什么我不能解析powers元素。
并请向我解释，因为我是编码新手，所以如何解析一个代码中的所有键和值。

Answer 1

所以问题在这里:

  doc[i] ["powers"] >> power;

doc[i]["powers"]没有索引“名称”:

• name: Ogre
  position: [0, 5, 0]
  powers:
  • name: Club
    damage: 10
  • name: Fist
    damage: 8

“-”表示项目。因此，类似于 doc[i]，您首先需要索引:

Power power;
doc[i]["powers"][0] >> power;
std::cout << power.name //outputs "Club"

但是我假设您希望每个项目都具有所有功能，因此您需要另一个显式的for循环:

for (unsigned i = 0; i < doc.size(); i++)
{
    for (unsigned j = 0; j < doc[i]["powers"].size(); ++j)
    {
        Power power;
        doc[i]["powers"][j] >> power;
        std::cout << power.name << "\n";
        std::cout << power.damage << "\n";
    }
}

但这有点矫kill过正。最好直接使用 Monster -class，因为功效值已存储在此处:

for(unsigned i=0;i<doc.size();i++) {
    Monster monster;
    doc[i] >> monster;

    for (auto& power : monster.powers) // range-for loop
    {
        std::cout << power.name << "\n";
        std::cout << power.damage << "\n";
    }
    std::cout << monster.name << "\n";
}

也许这是一个好的开始。答案的继续取决于您要实现的目标。