java - 如何在 Spring Boot 中抛出外部端点抛出的相同异常

Question

我正在访问外部 API，并且希望获得图像作为响应 (byte[])。我连接到此端点的方法如下所示:

 private byte[] retrieveImage(String uri) {
     byte[] imageBytes = null;
     try {
            URL url = new URL(uri);
            BufferedImage bufferedImage = ImageIO.read(url);
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            ImageIO.write(image, "png", baos);
            imageBytes = baos.toByteArray();
        } catch (Exception ex) {
            throw new ImageNotReadException(ex.getLocalizedMessage());
        }
        return imageBytes;
    }

事实证明，如果我将错误的参数传递给目标端点，我会收到以下错误消息:

所以基本上我想抛出上面相同的错误，但我也想抛出一个ImageNotReadException (java.lang. lang.IllegalArgumentException: image == null! )，以防程序无法读取图像 (byte[])。所以基本上，我的方法 private byte[]retrieveImage(String uri) 必须抛出读取图像异常和端点响应异常。

有什么建议吗？感谢您的帮助!

Answer 1

正如我所评论的，请参阅下面的选项

private Response retrieveImage(String uri) {
     byte[] imageBytes = null;
Response r=new Response();
     try {
            URL url = new URL(uri);
            BufferedImage bufferedImage = ImageIO.read(url);
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            ImageIO.write(image, "png", baos);
            imageBytes = baos.toByteArray();
            r.setImage(imageBytes);
            r.setStatus(1);
        } catch (Exception ex) {
            r.setStatus(0);
        }
        return r;
    }

回应:

class Response{ 
String status;
byte[] image;

//getters setters
}

或者:

  private Response retrieveImage(String uri)throws CustomException {
         byte[] imageBytes = null;
         try {
                URL url = new URL(uri);
                BufferedImage bufferedImage = ImageIO.read(url);
                ByteArrayOutputStream baos = new ByteArrayOutputStream();
                ImageIO.write(image, "png", baos);
                imageBytes = baos.toByteArray();
            } catch (Exception ex) {
                throw new CustomException(ex.getLocalizedMessage());
            }
            return imageBytes;
        }