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c++ - 给定二叉树,设计一种算法,该算法创建每个深度的所有节点的链表

转载 作者:行者123 更新时间:2023-12-02 10:25:37 25 4
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我试过在c++中实现相同。我想我差不多了,但是从链表访问节点时遇到错误。

list<list<Node*> > Binary_Tree::level(Node* node)
{
list<Node*> current,parent;
list<list<Node*> > result;

list<Node*>::iterator itr;
if (node != NULL)
current.push_back(node);

while(current.size() > 0)
{
result.push_back(current);
parent = current;

current.clear();
itr = parent.begin();
while(itr != parent.end())
{
if(itr->left != NULL) // I am getting an error here.error: request for member ‘right’ in ‘* itr.std::_List_iterator<_Tp>::operator-><Node*>()’, which is of pointer type ‘Node*’ (maybe you meant to use ‘->’ ?
current.push_back(itr->left);

if(itr->right != NULL)
current.push_back(itr->right);

itr++;
}

}

返回结果;
}

最佳答案

这是上述问题的解决方案。我把完整的代码。

#include <iostream>
#include <list>

using namespace std;
struct Node{

Node *left;
Node *right;
int data;
Node(int d)
{
left = NULL;
right = NULL;
data =d;
}
};
class Binary_Tree{

Node *root;
list<list<Node*> > level(Node*);
public:
Binary_Tree()
{
root = NULL;
}

void insert(int element);
list<list<Node*> > level();

};
void Binary_Tree::insert(int ele)
{
Node *node = new Node(ele);
if (root == NULL)
{
root = node;
return;
}
Node* temp = root;
while(temp != NULL)
{
if (ele > temp->data)
{
if(temp->right != NULL)
temp = temp->right;
else
{
temp->right = node;
return;
}
}
else
{
if(temp->left != NULL)
temp = temp->left;
else
{
temp->left = node;
return;
}
}
}
}
list<list<Node*> > Binary_Tree::level()
{
return level(root);
}
list<list<Node*> > Binary_Tree::level(Node* node)
{
list<Node*> current,parent;
list<list<Node*> > result;

list<Node*>::iterator itr;
if (node != NULL)
current.push_back(node);

while(current.size() > 0)
{
result.push_back(current);
parent = current;

current.clear();
itr = parent.begin();
while(itr != parent.end())
{
if((*itr)->left != NULL)
current.push_back((*itr)->left);

if((*itr)->right != NULL)
current.push_back((*itr)->right);

itr++;
}

}
return result;
}

int main()
{
list<list<Node*> >l;
list<list<Node*> >::iterator itr;
list<Node*>::iterator itr1;

Binary_Tree bt;
bt.insert(3);
bt.insert(2);
bt.insert(4);
bt.insert(1);
bt.insert(5);
l=bt.level();

itr = l.begin();
while(itr != l.end())
{

itr1 = (*itr).begin();
while(itr1 != (*itr).end())
{
cout<<(*itr1)->data<<" ";
itr1++;
}
cout<<endl;
itr++;

}

return 0;
}

关于c++ - 给定二叉树,设计一种算法,该算法创建每个深度的所有节点的链表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28779540/

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