c++ - 如何使2个功能起作用，而不是仅1个起作用

Question

我有2个void函数和一个主要函数。

但是由于第一个函数具有while(true)，因此它始终可以工作，并且由于第二个函数不起作用。如何使其同时工作？

   void shoot()
{
    *(DWORD*)(val.gameModule + offsets.ForceAttack, 5);
    Sleep(5000);
    *(DWORD*)(val.gameModule + offsets.ForceAttack, 4);
}

void bunny()
{


    val.gameModule = (DWORD)GetModuleHandle("client_panorama.dll");

    std::cout << (GetModuleHandle("client_panorama.dll")) << std::endl;;
    val.localPlayer = *(DWORD*)(val.gameModule + offsets.lplayer);
    while (true)
    {
        if (bunnyON == 1);
        else
            return;
        val.flag = *(BYTE*)(val.localPlayer + offsets.flags);
        if (isMoving())
            if (GetAsyncKeyState(VK_SPACE) && val.flag & (1 << 0))
                * (DWORD*)(val.gameModule + offsets.jump) = 6;
    }
}




int main()
{


    bunny();
    shoot();
}
`

Answer 1

尝试执行此操作，并检查这是否是您需要的:

#include <thread>

void shoot()
{
    *(DWORD*)(val.gameModule + offsets.ForceAttack, 5);
    Sleep(5000);
    *(DWORD*)(val.gameModule + offsets.ForceAttack, 4);
}

void bunny()
{
    val.gameModule = (DWORD)GetModuleHandle("client_panorama.dll");

    std::cout << (GetModuleHandle("client_panorama.dll")) << std::endl;;
    val.localPlayer = *(DWORD*)(val.gameModule + offsets.lplayer);
    while (true)
    {
        if (bunnyON == 1);
        else
            return;
        val.flag = *(BYTE*)(val.localPlayer + offsets.flags);
        if (isMoving())
            if (GetAsyncKeyState(VK_SPACE) && val.flag & (1 << 0))
                * (DWORD*)(val.gameModule + offsets.jump) = 6;
    }
}

int main()
{
    std::thread t1(bunny);
    std::thread t2(shoot);

    t1.join();
    t2.join();

    return 0;
}