AngularJS 嵌套 $http 调用

Question

我正在尝试编写一个工厂，它从两个源获取数据并使用一个源来扩展另一个对象中的数据。

app.factory('information', ['$http', '$q', 'players', 'matches', function($http, $q, players, matches) {
    return {
        // Returns all matches and players including extra parsing
        get: function() {
            return players.get().success(function(data) {
                players = data;

                matches.get().success(function(data) {
                    matches = data;

                    for ( match in matches ) {
                        matches[match].a_player1 = players.filter(function(player) { return player.username == matches[match].a_player1 })[0];
                        matches[match].a_player2 = players.filter(function(player) { return player.username == matches[match].a_player2 })[0];
                        matches[match].b_player1 = players.filter(function(player) { return player.username == matches[match].b_player1 })[0];
                        matches[match].b_player2 = players.filter(function(player) { return player.username == matches[match].b_player2 })[0];
                        console.log(matches)
                    }

                    return matches;
                });
            });
        },
    }
}]);

两者matches.get()和players.get()很简单GET对 API 的请求如下所示:

app.factory('players', function($http) {
    return {
        get: function() {
            return $http({
                method: 'GET',
                url: '/players',
            });
        },
    }
});

但是上面的代码(当然)返回 players对象，而我希望它返回 matches与 players 组合后的对象对象。

关于如何执行此操作有任何提示吗？

Answer 1

该函数不会返回任何内容，因为您无法直接从异步操作返回值，无论是返回 promise 还是使用回调。但我认为您正在寻找的是 $q.all:

return {
        // Returns all matches and players including extra parsing
        getEverything: function() {

        var getPlayers= $http({
            method: 'GET',
            url: '/players',
        });
        var getMatches= $http({
            method: 'GET',
            url: '/matches',
        });

           return $q.all([getPlayers,getMatches]);
        }
}

用法:

getEverything().then(function(data){
   var players=data[0].data;
   var matches=data[1].data;
})

编辑:

无关紧要，但要将其移回工厂:

getEverything: function() {
            var getPlayers= $http({
                method: 'GET',
                url: '/players',
            });
            var getMatches= $http({
                method: 'GET',
                url: '/matches',
            });
            return $q.all([getPlayers,getMatches]);
},
getEverythingMapped:function(){
 var deferred = $q.defer();
 this.getEverything().then(function(data){
       var players=data[0].data;
       var matches=data[1].data;
//do as many loops on either result set as you like
                for ( match in matches ) {
                    matches[match].a_player1 = players.filter(function(player) { return   player.username == matches[match].a_player1 })[0];
                    matches[match].a_player2 = players.filter(function(player) { return player.username == matches[match].a_player2 })[0];
                    matches[match].b_player1 = players.filter(function(player) { return player.username == matches[match].b_player1 })[0];
                    matches[match].b_player2 = players.filter(function(player) { return player.username == matches[match].b_player2 })[0];
                    console.log(matches)
//use of a promise here allows us top use this method using -then, we need to so this since we're
//waiting for the result of an async server call before we can loop through players and matches
                     deferred.resolve(matches);
                }


 }
}

现在您将在 Controller 中使用上述方法:

information.getEverythingMapped().then(function(matches){
 console.log(matches);
})