Java 跳过打印语句扫描器，具体

Question

所以我的问题是我想要求输入使用扫描仪的信息，但它根本不打印出来。当它显示跳过的扫描仪的值时，Scanner CheeseType = new Scanner(System.in);，我得到 null。

package classesProject;

import java.util.Scanner;

class Pizza {

    String size;
    String cheese;
    int numToppings;
    double price = 0;

}
public class pizzaTime {

    public static void main(String[] args) {

        Pizza order1 = new Pizza();

        double priceOfSize = 0;
        double priceOfCheese = 0;
        double priceOfToppings = 0;

        System.out.println("Pizza size small, medium or large: ");
        Scanner sizeAsker = new Scanner(System.in);
        order1.size = sizeAsker.nextLine();

        if(order1.size == "small") {
            priceOfSize = 3.0;

        } else if(order1.size == "medium") {
            priceOfSize = 5.0;

        } else if(order1.size == "large") {
            priceOfSize = 7.0;

        System.out.println("Cheese type: normal, xtra, or thic: ");
        Scanner cheeseType = new Scanner(System.in);
        order1.cheese = cheeseType.nextLine();

        }if(order1.cheese == "normal") {
            priceOfCheese = 0.0;

        } else if(order1.cheese == "xtra") {
            priceOfCheese = 0.5;

        } else if(order1.cheese == "thic") {
            priceOfCheese = 1.0;

        }

        System.out.println("Number of toppings: ");
        Scanner toppingAsker = new Scanner(System.in);
        order1.numToppings = toppingAsker.nextInt();

        priceOfToppings = order1.numToppings * 0.25;

        double orderTotalPrice = priceOfSize + priceOfCheese;

        System.out.println("Pizza size: " + order1.size + "\n"
                + "Cheese type: " + order1.cheese + "\n"
                + "Number of toppings: " + order1.numToppings + "\n"
                + "Order total: " + orderTotalPrice
                );

    }

}

被跳过的是:

System.out.println("Cheese type: normal, xtra, or thic: ");
Scanner cheeseType = new Scanner(System.in);
order1.cheese = cheeseType.nextLine();

运行后，控制台显示:

Pizza size small, medium or large: 
small
Number of toppings: 
2
Pizza size: small
Cheese type: null
Number of toppings: 2
Order total: 0.0

正如您所看到的，它直接从披萨尺寸扫描仪跳到配料数量扫描仪，而不是按顺序进行。我不知道为什么，或者我应该做什么来解决这个问题。

Answer 1

由于您在下一个问题后关闭括号，因此仅针对大披萨询问此问题

else if(order1.size == "large") {
        priceOfSize = 7.0;

    System.out.println("Cheese type: normal, xtra, or thic: ");
    Scanner cheeseType = new Scanner(System.in);
    order1.cheese = cheeseType.nextLine();

    }

如果您在priceOfSize = 7 之后添加右括号，则可以继续。不过，您仍然需要在其他地方修复丢失的括号。