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java - 如何识别与模式不匹配的数据

转载 作者:行者123 更新时间:2023-12-02 10:18:56 24 4
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因此,我使用匹配器类并使用它来识别我在枚举中定义的标记。

  public static enum TokenType {
// Definitions of accepted tokens
IF("if"), WHILE("while"), PRINT("print"), TYPE("int|string|boolean"), BOOLOP("==|!="), BOOLVAL("false|true"), INTOP("[+]"), CHAR("[a-z]"), DIGIT("[0-9]"), WHITESPACE("[ \t\f\r\n]+"), LPAREN("[(]"), RPAREN("[)]");
public final String pattern;

private TokenType(String pattern) {
this.pattern = pattern;
}
}

public static class Token {
public TokenType type;
public String data;

我的问题是,我还需要识别模式中未定义的任何内容,并在发生这种情况时打印错误。

这就是我的匹配器逻辑

    // Begin matching tokens
Matcher matcher = tokenPatterns.matcher(input);
while (matcher.find()) {
if (matcher.group(TokenType.DIGIT.name()) != null) {
tokens.add(new Token(TokenType.DIGIT, matcher.group(TokenType.DIGIT.name())));
continue;
} else if (matcher.group(TokenType.IF.name()) != null) {
tokens.add(new Token(TokenType.IF, matcher.group(TokenType.IF.name())));
continue;
} else if (matcher.group(TokenType.WHILE.name()) != null) {
tokens.add(new Token(TokenType.WHILE, matcher.group(TokenType.WHILE.name())));
continue;
} else if (matcher.group(TokenType.TYPE.name()) != null) {
tokens.add(new Token(TokenType.TYPE, matcher.group(TokenType.TYPE.name())));
continue;
} else if (matcher.group(TokenType.PRINT.name()) != null) {
tokens.add(new Token(TokenType.PRINT, matcher.group(TokenType.PRINT.name())));
continue;
} else if (matcher.group(TokenType.BOOLOP.name()) != null) {
tokens.add(new Token(TokenType.BOOLOP, matcher.group(TokenType.BOOLOP.name())));
continue;
} else if (matcher.group(TokenType.BOOLVAL.name()) != null) {
tokens.add(new Token(TokenType.BOOLVAL, matcher.group(TokenType.BOOLVAL.name())));
continue;
} else if (matcher.group(TokenType.INTOP.name()) != null) {
tokens.add(new Token(TokenType.INTOP, matcher.group(TokenType.INTOP.name())));
continue;
} else if (matcher.group(TokenType.CHAR.name()) != null) {
tokens.add(new Token(TokenType.CHAR, matcher.group(TokenType.CHAR.name())));
continue;
} else if (matcher.group(TokenType.LPAREN.name()) != null) {
tokens.add(new Token(TokenType.LPAREN, matcher.group(TokenType.LPAREN.name())));
continue;
} else if (matcher.group(TokenType.RPAREN.name()) != null) {
tokens.add(new Token(TokenType.RPAREN, matcher.group(TokenType.RPAREN.name())));
continue;
} else if (matcher.group(TokenType.WHITESPACE.name()) != null) {
continue;
}
}

return tokens;
}

一个可能的解决方案是在我的模式中添加一个案例,该案例解释了尚未定义的所有内容,看起来像这样 WHITESPACE("[\t\f\r\n]+"), LPAREN ("[(]"), ERROR("@|#,$,%,^,&.....") 但我不确定是否有任何现实的方法来实现这一点。

感谢您的帮助。这是完整代码的链接,以防我遗漏任何内容 - https://pastebin.com/jLtnJwgj

最佳答案

你尝试过这样的事情吗?

public class Lexer {

public static enum TokenType {
// Definitions of accepted tokens
IF("if"),
WHILE("while"),
PRINT("print"),
TYPE("int|string|boolean"),
BOOLOP("==|!="),
BOOLVAL("false|true"),
INTOP("[+]"),
CHAR("[a-z]"),
DIGIT("[0-9]"),
WHITESPACE("[ \t\f\r\n]+"),
LPAREN("[(]"),
RPAREN("[)]"),
OTHER(".");
public final String pattern;

private TokenType(final String pattern) {
this.pattern = pattern;
}
}

public static class Token {
public TokenType type;
public String data;

public Token(final TokenType type, final String data) {
this.type = type;
this.data = data;
}
}

public static ArrayList<Token> lex(final String input) {
// The tokens to return
final ArrayList<Token> tokens = new ArrayList<Token>();

// allows us to work with a mutable string
final StringBuffer tokenPatternsBuffer = new StringBuffer();

for (final TokenType tokenType : TokenType.values()) {
tokenPatternsBuffer.append(String.format("|(?<%s>%s)",
tokenType.name(), tokenType.pattern));
}
final Pattern tokenPatterns = Pattern.compile(
new String(tokenPatternsBuffer.substring(1)));

// Begin matching tokens
String other = "";
final Matcher matcher = tokenPatterns.matcher(input);
while (matcher.find()) {
if (matcher.group(TokenType.DIGIT.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.DIGIT,
matcher.group(TokenType.DIGIT.name())));
continue;
} else if (matcher.group(TokenType.IF.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.IF,
matcher.group(TokenType.IF.name())));
continue;
} else if (matcher.group(TokenType.WHILE.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.WHILE,
matcher.group(TokenType.WHILE.name())));
continue;
} else if (matcher.group(TokenType.TYPE.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.TYPE,
matcher.group(TokenType.TYPE.name())));
continue;
} else if (matcher.group(TokenType.PRINT.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.PRINT,
matcher.group(TokenType.PRINT.name())));
continue;
} else if (matcher.group(TokenType.BOOLOP.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.BOOLOP,
matcher.group(TokenType.BOOLOP.name())));
continue;
} else if (matcher.group(TokenType.BOOLVAL.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.BOOLVAL,
matcher.group(TokenType.BOOLVAL.name())));
continue;
} else if (matcher.group(TokenType.INTOP.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.INTOP,
matcher.group(TokenType.INTOP.name())));
continue;
} else if (matcher.group(TokenType.CHAR.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.CHAR,
matcher.group(TokenType.CHAR.name())));
continue;
} else if (matcher.group(TokenType.LPAREN.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.LPAREN,
matcher.group(TokenType.LPAREN.name())));
continue;
} else if (matcher.group(TokenType.RPAREN.name()) != null) {
other = unknow(tokens, other);
tokens.add(new Token(TokenType.RPAREN,
matcher.group(TokenType.RPAREN.name())));
continue;
} else if (matcher.group(TokenType.WHITESPACE.name()) != null) {
continue;
} else if (matcher.group(TokenType.OTHER.name()) != null) {
other += matcher.group(TokenType.OTHER.name());
continue;
}
}
other = unknow(tokens, other);
return tokens;
}

private static String unknow(final ArrayList<Token> tokens, final String _unknow) {
if (!_unknow.isEmpty()) {
tokens.add(new Token(TokenType.OTHER,_unknow));
}
return "";
}

public static void main(final String[] args) {
final String input = "if\nprint\nta!?!?!taelse?§.?toto";
// Create tokens and print them
final ArrayList<Token> tokens = lex(input);
for (final Token token : tokens)
System.out.println("DEBUG Lexer - " + token.type + " [ "
+ token.data + " ] " + "found at " + "linenumber");
}

}

关于java - 如何识别与模式不匹配的数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54481302/

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