c++ - 通过引用将对象传递给函数不会更改此对象

Question

所以基本上，我试图将对象传递给我的函数Attack():

void Character::Attack(Character &another, short int range)
{
    if (EnemyInRange(range) && another.health > 0)
    {
        if (allowed_to_attack)
        {
            attacked = true;

            cout << name << " attacked " << another.name << " taking " << attack << " damage" << endl;


            if (another.defensive > 0) // less important things down there
            {
                another.defensive--;

                if (attack > another.defensive)
                {
                    another.health -= (attack - another.defensive);
                }
            }
            else if (another.defensive == 0)
            {
                another.health -= attack;
            }


            if (another.defensive <= 0)
                another.defensive = 0;

            if (another.health <= 0)
            {
                another.health = 0;
                another.draw = false;
                another.~Character();
            }

        }

        else
        {
            attacked = false;
            cout << "Blocked" << endl;
        }

    }
    else
        cout << name << " wanted to attack " << another.name << " ,but he's out of the range" << endl;

如您所见，我正在使用引用传递对象。但是，当我调用此函数时:

void onClick(Vector2f mouse_position, Character current, Character *& target, Position &positionx)
{
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 5; j++)
        {
            if ((mouse_position.x >= 245 + i * 164 && mouse_position.x <= 370 + i * 164) &&
                (mouse_position.y >= 56 + j * 201 && mouse_position.y <= 221 + j * 201))
            { // there's a 2d map with cards on those positions
                target = &positionx.positioning[i][j];
                current.Attack(*target);
            }
        }
    }

}

positioning is an array filled with characters

行为就像我传递了一个对象目标的副本(它写出名称，但不会改变其运行状况)

在main()中，它看起来像这样:

Character *current = new Character();
Character *target = NULL;

if ((event.type == Event::MouseButtonPressed) && (event.mouseButton.button == Mouse::Left))//SFML lib
{
    Vector2i pos = Mouse::getPosition(window);
    Vector2f position = (Vector2f)pos;
    onClick(position, *current, target, positionx);
} // target is selected after clicking on it

Answer 1

在onClick函数中，变量current通过值而不是引用传递。我假设应该通过引用传递:

void onClick(Vector2f mouse_position, Character &current, Character *target, Position &positionx)

请注意，参数 current已更新为引用。

编辑:

查看 Attack函数的主体，如果满足打印输出名称的行，您确定满足if-condition语句 if(another.defensive > 0)和 if(attack > another.defensive)吗？