c++ - 我们可以通过c++中的运算符重载将一个类的数据转换为另一个类吗？

Question

我有2个类Employee和Person。 Employee类具有name，age和salary三个属性。 Person类具有name和age属性。我想重载赋值运算符，以将Employee类的名称和年龄分配给name和age的人类。

class Employee {
    string name;
    int age;
    float salary;
public:
    Employee()
    {
        name="";
        age=0;
        salary=0;

    }
    void operator =(const Employee& a)
    {
        name=a.name;
        age=a.age;
    }

};

class Person {
    string name;
    int age;
public:
    Person()
    {
        name="";
        age=0;
    }
    void display()
    {
        cout<<"Name are :"<<name<<endl;
        cout<<"Age are  :"<<age<<endl;
    }
};

int main()
{
    Employee obj;
    person obj1;
    obj=obj1;     
}

Answer 1

这是上述问题的答案

#include <iostream>
#include <string>
using namespace std;

class Employee {
private:
    string name;
    int age;
    float salary;

public:

    // default constructor (meaning less) 
    Employee() {
        name   =   "";
        age    =   0;
        salary =   0.0;
    }

    // Parameterized constructor
    Employee(string name, int age, float salary) {
        this->name   = name;
        this->age    = age;
        this->salary = salary;
    }

    // getter members to
    // get value of private members
    // from outside class
    string getName() {
        return this->name;
    }

    int getAge() {
        return this->age;
    }

    float getSalary() {
        return this->salary;
    }
    };
   class Person: Employee {
    private:
    string name;
    int age;
    public:
    Person() {
        name = "";
        age  = 0;
    }

    void operator = (Employee &emp) {
        this->name = emp.getName();
        this->age  = emp.getAge();
    }
    void display() {
        cout << "Name is : " << name << endl;
        cout << "Age is  : " << age << endl;
    }
}; 
int main() {
Employee emp("Emp", 25, 45000.00);
Person p1;

p1 = emp;
p1.display();
return 0;

}