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java - Apache HttpClient,基于表单的登录,不检索 HTML 内容

转载 作者:行者123 更新时间:2023-12-02 10:15:38 25 4
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我正在使用 apache 的 Httpclient 来访问基于表单的登录身份验证背后的另一个页面,但是,我收到的结果是相同的基于表单的登录页面。

我应该做一些不同的事情吗?

public static void main(String[] args) throws ClientProtocolException, IOException, InterruptedException {
CloseableHttpClient httpclient = HttpClients.createDefault();
HttpPost httppost = new HttpPost("http://localhost/salvaurls/");

// Request parameters and other properties.
List<NameValuePair> params = new ArrayList<NameValuePair>(4);
params.add(new BasicNameValuePair("return_url", "http://localhost/salvaurls/painel.php"));
params.add(new BasicNameValuePair("action", "http://localhost/salvaurls/autenticacao.php?acao=login"));
params.add(new BasicNameValuePair("login", "desenvolvimento@gmail.com.br"));
params.add(new BasicNameValuePair("senha", "123"));
UrlEncodedFormEntity entity_ = new UrlEncodedFormEntity(params, Consts.UTF_8);
httppost.setEntity(entity_);

//Execute and get the response.
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();

if (entity != null) {
try (InputStream is = entity.getContent()) {
System.out.println("entrou");
Thread.sleep(2000);

BufferedReader br = new BufferedReader(new InputStreamReader(is));
String str ="";
while ((str = br.readLine()) != null){
System.out.println(""+str);
}
}
}
}

index.html - 运行代码后显示的登录表单:

<body id="LoginForm">
<div class="container">
<h1 class="form-heading">login Form</h1>
<div class="login-form">
<div class="main-div">
<div class="panel">
<h2>Salva URLs</h2>
<p>Please enter your email and password</p>
</div>
<form id="Login" action="autenticacao.php?acao=login" method="post">
<div class="form-group">
<input type="email" class="form-control" id="login" name="login"
placeholder="Email Address">
</div>
<div class="form-group">
<input type="password" class="form-control" id="senha" name="senha"
placeholder="Password">
</div>
<div class="forgot">
<a href="reset.html">Forgot password?</a>
</div>
<button type="submit" class="btn btn-primary">Login</button>
</form>
</div>
</div>
</div>
</div>
</body>

最佳答案

您根本没有调用登录网址。将 HttpPost url 更改为 http://localhost/salvaurls/autenticacao.php?acao=login 并从列表中删除操作参数。

HttpPost httppost = new HttpPost("http://localhost/salvaurls/autenticacao.php?acao=login");

// Request parameters and other properties.
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("return_url", "http://localhost/salvaurls/painel.php"));
params.add(new BasicNameValuePair("login", "desenvolvimento@gmail.com.br"));
params.add(new BasicNameValuePair("senha", "123"));

通常,如果您已成功通过身份验证,服务器会发送 cookie。对于进一步的请求,您可能需要 cookie 存储。

CookieStore cookieStore = new BasicCookieStore();
HttpClientContext context = HttpClientContext.create();
context.setAttribute(HttpClientContext.COOKIE_STORE, cookieStore);
HttpClient client = HttpClients.createDefault();

HttpPost httppost = new HttpPost("http://localhost/salvaurls/autenticacao.php?acao=login");

// Request parameters and other properties.
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("return_url", "http://localhost/salvaurls/painel.php"));
params.add(new BasicNameValuePair("login", "desenvolvimento@gmail.com.br"));
params.add(new BasicNameValuePair("senha", "123"));
UrlEncodedFormEntity entity_ = new UrlEncodedFormEntity(params, Consts.UTF_8);
httppost.setEntity(entity_);

HttpResponse response = client.execute(httppost, context);
String response = EntityUtils.toString(response.getEntity());

如果您要进行进一步的身份验证请求,则每次都需要将 HttpClientContext 与 cookie 存储一起使用。希望有帮助。

关于java - Apache HttpClient,基于表单的登录,不检索 HTML 内容,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54709551/

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