- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
JLS 5.1.9定义未经检查的转换如下:
Let G name a generic type declaration with n type parameters.
There is an unchecked conversion from the raw class or interface type G to any parameterized type of the form
G<T1,...,Tn>
.There is an unchecked conversion from the raw array type
G[]
to any array type type of the formG<T1,...,Tn>[]
.Use of an unchecked conversion causes a compile-time unchecked warning unless
G<...>
is a parameterized type in which all type arguments are unbounded wildcards, or the unchecked warning is suppressed by the SuppressWarnings annotation
据我所知,它表示如果将原始类型强制转换为具有有界类型参数的泛型类型,则会发生未经检查的转换。那么为什么以下代码会生成未经检查的警告:
public class DoubleStar{
public static void print(Object object){
((A<String>)object).print();
}
public static void main(String[] args){
print(new Object());
}
}
class A<T>{
public void print(){
System.out.print("HELLO");
}
}
由于对象不是原始类型(AFAIK)为什么上面的代码会生成未经检查的强制转换警告以及此行为是在哪里定义的?
最佳答案
您正在查看错误的部分,这就是为什么它在您的示例上下文中似乎没有意义。
您收到的警告是未经检查的强制转换。您正在查看有关未检查转化的部分 ( related )。
See 5.5.2 "Checked Casts and Unchecked Casts"
A cast from a type S to a type T is statically known to be correct if and only if S <: T (§4.10).
A cast from a type S to a parameterized type (§4.5) T is unchecked unless at least one of the following conditions holds:
- S <: T
- All of the type arguments (§4.5.1) of T are unbounded wildcards
- T <: S and S has no subtype X other than T where the type arguments of X are not contained in the type arguments of T.
A cast from a type S to a type variable T is unchecked unless S <: T.
An unchecked cast from S to T is completely unchecked if the cast from |S| to |T| is statically known to be correct. Otherwise, it is partially unchecked.
An unchecked cast causes a compile-time unchecked warning, unless suppressed by the SuppressWarnings annotation (§9.6.3.5).
A cast is checked if it is not statically known to be correct and it is not unchecked.
If a cast to a reference type is not a compile-time error, there are several cases:
- The cast is statically known to be correct.
No run-time action is performed for such a cast.
- The cast is a completely unchecked cast.
No run-time action is performed for such a cast.
- The cast is a partially unchecked cast.
Such a cast requires a run-time validity check. The check is performed as if the cast had been a checked cast between |S| and |T|, as described below.
- The cast is a checked cast.
Such a cast requires a run-time validity check. If the value at run time is null, then the cast is allowed. Otherwise, let R be the class of the object referred to by the run-time reference value, and let T be the erasure (§4.6) of the type named in the cast operator. A cast conversion must check, at run time, that the class R is assignment compatible with the type T, via the algorithm in §5.5.3.
Note that R cannot be an interface when these rules are first applied for any given cast, but R may be an interface if the rules are applied recursively because the run-time reference value may refer to an array whose element type is an interface type.
关于java - 对象到泛型类型转换的未检查警告的定义在哪里?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54979291/
可以用这种方式转换字符串吗?我们有相同的参数,Java 做出了正确的选择。如果值是整数 - 我们调用 parseInt(value),否则如果值是 double 型 - 我们调用 parseDoubl
如果这段代码中有一个愚蠢的错误,我提前道歉,但我似乎无法解决它。我的问题是这样的,我用GCC-8(通过home-brew安装在Mac上)编译,然后在终端中执行。当使用 int do 定义变量 s &
我用 a-videosphere 制作了一个 a-scene。我尝试使用按钮启用/禁用声音,但有些想法不起作用?这是我的代码: var gargamel = 0; function
我正在使用 ISAAC 实现来生成随机整数。我需要用这些整数创建一个高斯值。首先,我需要将它们从 0 更改为 1 的 double 值。我怎样才能在Java中做到这一点?这是到目前为止我将整数转换为
我将 0x0000 到 0x01c2 范围内的十六进制值从 BLE 获取到我的手机 a 作为字符串。为了将其绘制在图表中,我必须将其转换为 double,我已经尝试过 this method但遗憾的是
我有一个父类(super class) Animal和一个子类 Dog 。在第三节课中,我有一个 List它同时接受子类型和父类(super class)型对象。 public class foo{
关闭。这个问题需要多问focused 。目前不接受答案。 想要改进此问题吗?更新问题,使其仅关注一个问题 editing this post . 已关闭 6 年前。 Improve this ques
我正在尝试查询我的用户的距离。我可以用这段代码做到这一点 PFGeoPoint.geoPointForCurrentLocationInBackground { (geoPoint: PFGe
考虑示例:http://jsfiddle.net/KWLu7/16/ 我正在尝试将总体重要性值计算为每个选定选择重要性的总和乘以其父标准重要性: var watch = $scope.$watch("
这个问题在这里已经有了答案: Bounding generics with 'super' keyword (6 个答案) 关闭 2 年前。 我有一个列表装饰器,它应该允许从一个列表转换到另一个列表
为什么下面的代码没有选择最近父类(super class)型的隐式 val? class A class B extends A trait TC[-T] { def show(t: T): Stri
这是我想要做的 def merge[A, B, C](eithers: Either[A,B]*)(implicit ev1: A x, x => x)) 关于scala - 推断常见的父类(s
我正在尝试从具有 double 类型列的Cassandra表中获取 double 值。我已经使用CQL3语法创建了表: CREATE TABLE data_double ( datetime
是否应该在不需要显式类型定义的情况下编译以下 this ? def prepList[B >: A](prefix: PlayList[B]) : PlayList[B] = prefix.fol
我正在查看某人的代码,并且在创建结构时使用了 abstract type AbstractFoo end julia> struct Foo1 struct Foo2 foo_op(x::Abst
一些示例代码: public class Main { class SomeType { } class A { protected T createSome
是否可以只接受类的泛型类型的父类(super class)型? 我正在寻找的是这样的: class MyClass { public void myMethod(TS someObject
在我的代码中,我有许多 ArrayList 被传递到排序方法中。每个 ArrayList 都有不同的泛型类型,但所有这些类型都是 Sorter 的实现。排序方法旨在接受 Sorter 类型的 Arra
如果已经有人问过这个问题,请链接并关闭这个问题。 我目前正在为另一个使用起来复杂得多(并且有潜在危险)的 API 的简化 API 设计原型(prototype)。 考虑到相关的有点复杂的对象创建,我决
我正在尝试构建一个具有某些依赖项的 android 应用程序,但是其中一个导致了此错误: Illegal class file: Class module-info is missing a supe
我是一名优秀的程序员,十分优秀!