xslt - 使用 xslt 查找表替换子字符串

Question

我有一些包含十六进制字符串变体的字符串(来源是framemaker，如果有人关心的话)。因此，字符串可能看起来像

this is some sentence with some hex code\x27 s , and we need that fixed.

并且需要更改为

this is some sentence with some hex code's , and we need that fixed.

实际上，单个字符串中可能有其中一些，因此我正在寻找遍历文本、捕获所有十六进制代码(看起来像\x## )并将所有这些代码替换为的最佳方法正确的字符。我制作了一个 xml 列表/查找表，其中包含所有字符，如下所示:

<xsl:param name="reflist">
    <Code Value="\x27">'</Code>
<Code Value="\x28">(</Code>
<Code Value="\x29">)</Code>
<Code Value="\x2a">*</Code>
<Code Value="\x2b">+</Code>
    <!-- much more like these... -->
</xsl:param>

现在我使用了一个简单的替换参数，但字符太多，无法实现。

最好的方法是什么？

Answer 1

人们可以完全避免使用任何“引用表”——就像这样:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:xs="http://www.w3.org/2001/XMLSchema"
 xmlns:my="my:my" exclude-result-prefixes="my xs">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="text()[matches(.,  '\\x(\d|[a-f])+')]">
   <xsl:analyze-string select="." regex="\\x(\d|[a-f])+" >
     <xsl:matching-substring>
       <xsl:value-of select=
       "codepoints-to-string(my:hex2dec(substring(.,3), 0))"/>
     </xsl:matching-substring>
     <xsl:non-matching-substring>
      <xsl:value-of select="."/>
     </xsl:non-matching-substring>
   </xsl:analyze-string>
 </xsl:template>

 <xsl:function name="my:hex2dec" as="xs:integer">
  <xsl:param name="pStr" as="xs:string"/>
  <xsl:param name="pAccum" as="xs:integer"/>

  <xsl:sequence select=
   "if(not($pStr))
     then $pAccum
     else
      for $char in substring($pStr, 1, 1),
          $code in
            if($char ge '0' and $char le '9')
              then xs:integer($char)
              else
                string-to-codepoints($char) - string-to-codepoints('a') +10
       return
          my:hex2dec(substring($pStr,2), 16*$pAccum + $code)
   "/>
 </xsl:function>
</xsl:stylesheet>

当此转换应用于以下 XML 文档时:

<t>
 <p>this is some sentence with some hex code\x27 s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x28 s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x29 s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2a s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2b s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2c s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2d s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2e s ,
    and we need that fixed.</p>
 <p>this is some sentence with some hex code\x2f s ,
    and we need that fixed.</p>
</t>

产生了想要的正确结果:

<t>
   <p>this is some sentence with some hex code' s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code( s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code) s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code* s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code+ s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code, s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code- s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code. s ,
    and we need that fixed.</p>
   <p>this is some sentence with some hex code/ s ,
    and we need that fixed.</p>
</t>

请注意:

此转换是通用的，可以正确处理任何十六进制 unicode 代码。

例如，如果对此 XML 文档应用相同的转换:

<t>
 <p>this is some sentence with some hex code\x0428\x0438\x0448 s ,
    and we need that fixed.</p>
</t>

生成正确的结果(包含保加利亚语中的西里尔字母“烧烤”):

<t>
   <p>this is some sentence with some hex codeШиш s ,
    and we need that fixed.</p>
</t>