gpt4 book ai didi

java - 程序将 *.csv 文件读取到数组中并打印内容。需要打印索引号

转载 作者:行者123 更新时间:2023-12-02 10:03:21 28 4
gpt4 key购买 nike

我正在尝试将索引号包含到我的 println 字符串中。我尝试创建迭代循环,但它无法正确打印索引号。

package main;
import test.address;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;

public class Lab9_main {

// Delimiters used in the CSV file
private static final String COMMA_DELIMITER = ",";

public static void main(String[] args) {

BufferedReader br = null;

try {

// Reading the csv file
br = new BufferedReader(new FileReader("addresses.csv"));

// Create List for holding address objects
ArrayList<address> addressList = new ArrayList<>();

String line;

// Read to skip the header
br.readLine();

// Reading from the second line
while ((line = br.readLine()) != null) {
String[] addressDetails = line.split(COMMA_DELIMITER);

//Save the address details in address object
if(addressDetails.length > 0 ) {
address addy = new address(addressDetails[0], addressDetails[1], addressDetails[2],
addressDetails[3], addressDetails[4], Integer.parseInt(addressDetails[5]));
addressList.add(addy);
}
}

// Lets print the address List
for(address e : addressList) {
System.out.println("The address details in the index....." + e + "....:" + e.getFirstName()
+ "..." + e.getLastName() + "..." + e.getAdd() + "...." + e.getCit() + ".. " + e.getSt()
+ "..." + e.getZip());

}

} catch(Exception ee) {
ee.printStackTrace();
}

finally {
try {
br.close();
} catch(IOException ie) {
System.out.println("Error occurred while closing the BufferedReader");
ie.printStackTrace();
}
}
}
}

当前的打印输出如下所示:

The address details in the index.....test.address@61bbe9ba....:John...Doe...120 jefferson st.....Riverside..  NJ...80751
The address details in the index.....test.address@610455d6....:Jack...McGinnis...220 hobo Av.....Phila.. PA...9119

我想要显示索引号而不是地址位置,例如:

The address details in the index.....0....:John...Doe...120 jefferson st.....Riverside..  NJ...80751
The address details in the index.....1....:Jack...McGinnis...220 hobo Av.....Phila.. PA...9119

最佳答案

For-Each Loop您正在使用的将迭代集合,而不会暴露您手中的元素的索引。

试试这个:

//Lets print the Employee List
for(int i = 0; i < addressList.size(); i++) {
address e = addressList.get(i);
System.out.println("The address details in the index....." + i + "....:" + e.getFirstName()
+ "..." + e.getLastName() + "..." + e.getAdd() + "...." + e.getCit() + ".. " + e.getSt()
+ "..." + e.getZip());

}

关于java - 程序将 *.csv 文件读取到数组中并打印内容。需要打印索引号,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55477437/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com