c++ - 将变量添加到 vector 列表的C++问题

Question

我创建了一个程序，该程序可以读取不同的文本文件并将每个文件存储在其自己的Vector列表中。但是，该程序的 vector 列表比例不起作用。下面提供的是当前正在使用的文本文件以及程序本身

文本文件

A:Head:1:2:15.
B:Torso:0:6:5.
C:Leg:0:4:6.
D:Arm:0:4:8.
E:Tail:0:6:2.

主文件

#include <iostream>
#include <string>
#include <conio.h>
#include <stdio.h>
#include "driver.h"
#include "implementation.cpp"
#include <fstream>
#include <vector>
using namespace std;

int main() {
readFile();
writeFile();
robotComplexity();
getch();
return 0;
}

包含功能的实现文件

#include <iostream>
#include <string>
#include <sstream> 
#include <fstream>
#include <fstream>
#include <vector>
using namespace std;

//declaration of parts variables
char partCode;
std::string partName;
int maximum;
int minimum;
int complexity;

std::vector<string> partsVector;
std::ifstream partsList("Parts.txt");
std::string outputFile = "output.txt";
std::string input;

std::string newChar;
std::stringstream convertChar;

void readFile() //function to read Builders, Customers and Parts text file
{

   std::string line;

while (std::getline(partsList, line)) {
    line.pop_back();//removing '.' at end of line
    std::string token;
    std::istringstream ss(line);

    convertChar << partCode;
    convertChar >> newChar;


    // then read each element by delimiter
    int counter = 0;//number of elements you read
    while (std::getline(ss, token, ':')) {//spilt into different records
      switch (counter) {//put into appropriate value-field according to element-count

      case 0:
        newChar = token; //convert partCode from a char to a string 
        break;
      case 1:
        partName = token;
        break;
      case 2: maximum = stoi(token);
        break;
      case 3: minimum = stoi(token);
        break;
        case 4: complexity = stoi(token);
        break;
      default:
        break;
      }
      counter++;//increasing counter
    }

    partsVector.push_back(newChar);

    for(string x: partsVector)
    cout << x << endl;
}

}


double robotComplexity() { 


double complexity;

for(int i = 1; i < partsVector.size(); i++)
/*
if(newChar == "A") {
   cout << "Character: " << newChar;
} else   {
   cout << "Program isnt working! :(";


} */
   if(complexity > 100) {
      complexity = 100;
   }


cout << "\nThe Robot Complexity is: " << complexity << endl;
return complexity;
}


double robotVariability() {

double variability;


cout << "\nThe Robot Variability is: " << variability << endl;
return variability;

}

void writeFile() //writes to a file output.txt the end calculations. 
{

}

我目前遇到问题的代码如下

while (std::getline(partsList, line)) {
    line.pop_back();//removing '.' at end of line
    std::string token;
    std::istringstream ss(line);

    convertChar << partCode;
    convertChar >> newChar;

    // then read each element by delimiter
    int counter = 0;//number of elements you read
    while (std::getline(ss, token, ':')) {//spilt into different records
      switch (counter) {//put into appropriate value-field according to element-count

      case 0:
        newChar = token; //convert partCode from a char to a string 
        break;
      case 1:
        partName = token;
        break;
      case 2: maximum = stoi(token);
        break;
      case 3: minimum = stoi(token);
        break;
        case 4: complexity = stoi(token);
        break;
      default:
        break;
      }
      counter++;//increasing counter
    }

    partsVector.push_back(newChar);

    for(string x: partsVector)
    cout << x << endl;
}

编译并执行此程序后，会将以下内容打印到控制台

A
A
B
A
B
C
A
B
C
D
A
B
C
D
E

这显然是错误的，因为应该按照我的程序规范的要求打印每个字母之一。

A
B
C
D
E

这样做的目的是让我知道该功能可以成功识别每个记录。要注意的是，这与其他变量(例如partName)一起发生。我已经推断出这是我如何将变量添加到 vector 中的一个问题，但是我不确定为什么。任何帮助将是巨大的谢谢。

Answer 1

因此，问题很简单，就是您在哪里打印出partsVector，它应该在读取循环之后才在读取循环内。所以应该是这个

while (std::getline(partsList, line)) {
    ...
    partsVector.push_back(newChar);
}

for(string x: partsVector)
    cout << x << endl;

代替这个

while (std::getline(partsList, line)) {
    ...
    partsVector.push_back(newChar);
    for(string x: partsVector)
        cout << x << endl;
}

因为在读入零件时打印零件 vector ，所以将显示这些重复的值。