java - cucumber 测试步骤在 J-Unit 中未显示，而在控制台步骤中已成功运行

Question

我目前正在尝试创建我的第一个 Cucumber 测试。在 Java Eclipse 中，我创建了一个包含以下内容的“功能文件”:

Feature: Login functionality DemoQA.com

Scenario: Verify if user is able to login to the DemoQA website
    Given A user is on DemoQA.com
    When User clicks MyAccount link
    Then User is taken to Login Page
    When User enters valid username and password
    Then User is able to login 

我还创建了以下测试运行程序文件:

@RunWith(Cucumber.class)
@CucumberOptions(   
        features = "src/test/Features/",
        glue = {"Tests"}
        )
public class CucumberRunner {
}

我还创建了我的步骤定义:

公共(public)类LoginStepDefinitions {

@Given("A user is on DemoQA.com")
public void a_user_is_on_DemoQA_com() {

     System.setProperty("webdriver.gecko.driver","C:\\geckodriver-v0.10.0-win64\\geckodriver.exe");

         WebDriver driver = new FirefoxDriver();
         WebDriverWait wait = new WebDriverWait(driver, 50);

         String url = "https://demoqa.com";

            //Launch the Online Store Website
            driver.get(url);

try {

            wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//*[@id=\"logo-events\"]/a/img")));   
            driver.findElement(By.xpath("//*[@id=\"logo-events\"]/a/img"));
            System.out.println("User has succesfully opened DemoQA.com");

             } 

catch (Exception e) {
            System.out.println("User was not able to open DemoQA.com");

            }

}

@When("User clicks MyAccount link")
public void user_clicks_MyAccount_link() {
    // Write code here that turns the phrase above into concrete actions
    System.out.println("User clicks on the MyAccount link");
}

@Then("User is taken to Login Page")
public void user_is_taken_to_Login_Page() {
    System.out.println("User is succesfully taken to MyAccount login");
}

@When("User enters valid username and password")
public void user_enters_valid_username_and_password() {
    System.out.println("User enters valid credentials for MyAccount login");
}

@Then("User is able to login")
public void user_is_able_to_login() {
    // Write code here that turns the phrase above into concrete actions
    System.out.println("User is succesfully logged in");
}

}

当我将脚本作为 Junit 测试运行时，控制台成功执行测试并显示结果:

User has succesfully opened DemoQA.com
[32m.[0mUser clicks on the MyAccount link
[32m.[0mUser is succesfully taken to MyAccount login
[32m.[0mUser enters valid credentials for MyAccount login
[32m.[0mUser is succesfully logged in
[32m.[0m
1 Scenarios ([32m1 passed[0m)
5 Steps ([32m5 passed[0m)
0m7.706s

但是当打开 JUnit 选项卡时会发生两件事:

1)测试步骤似乎没有显示:

2) 当我双击功能/场景步骤时，我收到一条消息:

在所选项目中找不到测试类

阅读了有关此主题的其他一些帖子后，我的第一个想法是我的功能文件未位于正确的文件夹中，但我现在几乎已将其移动到任何地方，而且似乎没有任何区别。

这是我当前在 Eclipse 中的结构:

有人可以帮帮我吗？谢谢!

Answer 1

@CucumberOptions 中的答案 'junit = "--step-notifications"' 对我不起作用。但幸运的是，我立即找到了解决方案。

@CucumberOptions
(
    features="path to feature file",

    glue="path to step definition file",

    stepNotifications = true
)