c++ - 有没有办法从字符串输出cout中的反斜杠符号？

Question

C++代码

fs::path pathToShow("C:\Windows\system.ini");
cout << "exists() = " << fs::exists(pathToShow) << "\n"
    << "root_name() = " << pathToShow.root_name() << "\n"
    << "root_path() = " << pathToShow.root_path() << "\n"
    << "relative_path() = " << pathToShow.relative_path() << "\n"
    << "parent_path() = " << pathToShow.parent_path() << "\n"
    << "filename() = " << pathToShow.filename() << "\n"
    << "stem() = " << pathToShow.stem() << "\n"
    << "extension() = " << pathToShow.extension() << "\n";

摘自 https://www.codingame.com的示例

输出量

exists() = 0
root_name() = "C:"
root_path() = "C:"
relative_path() = "Windowssystem.ini"
parent_path() = "C:"
filename() = "Windowssystem.ini"
stem() = "Windowssystem"
extension() = ".ini"
Press any key to continue . . .

Visual Studio是否具有编译器/链接器选项来威胁'\'符号为

\\

用cout或printf输出时？还是有另外一种简单的方法，而无需创建自己的函数来操作字符串(无需太费劲)？

Answer 1

不是编译器选项，而是语言功能:使用raw string literal。应该适用于所有编译器。

fs::path pathToShow(R"(C:\Windows\system.ini)");