in-app-purchase - Google Play API返回错误

Question

我遇到了this post中所述的相同问题

。我们使用了几乎完全相同的代码。我在mehotd下面尝试了客户ID和谷歌服务帐户的电子邮件地址

setServiceAccountId(GOOGLE_SERVICE_CLIENT_EMAIL) OR
setServiceAccountId(GOOGLE_CLIENT_ID)

错误随着A / C ID的变化而变化。如果我使用客户端ID，则错误为

400 Bad Request { "error" : "invalid_grant" }

如果我使用服务电子邮件ID，则错误为

401 Unauthorized {   
"code" : 401,   "errors" : [ {
    "domain" : "androidpublisher",
    "message" : "This developer account does not own the application.",
    "reason" : "developerDoesNotOwnApplication"   } ],   "message" : "This developer account does not own the application." }

任何的想法？

Answer 1

似乎有证据表明Google Play API当前不适用于服务帐户(疯狂)。关于问题here，还有另一个主题。您可以阅读有关Google服务帐户here的信息。您可以阅读有关Android Google Play API here的身份验证的信息。

在Google API控制台上完成跳舞以获取refresh_token之后，您将获得如下访问 token :

private String getAccessToken()
{

    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost("https://accounts.google.com/o/oauth2/token");
    try 
    {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);
        nameValuePairs.add(new BasicNameValuePair("grant_type",    "refresh_token"));
        nameValuePairs.add(new BasicNameValuePair("client_id",     "YOUR_CLIENT_ID);
        nameValuePairs.add(new BasicNameValuePair("client_secret", "YOUR_CLIENT_SECRET"));
        nameValuePairs.add(new BasicNameValuePair("refresh_token", "YOUR_REFRESH_TOKEN"));
        post.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        HttpResponse response = client.execute(post);
        BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
        StringBuffer buffer = new StringBuffer();
        for (String line = reader.readLine(); line != null; line = reader.readLine())
        {
            buffer.append(line);
        }

        JSONObject json = new JSONObject(buffer.toString());
        return json.getString("access_token");
    }
    catch (IOException e) { e.printStackTrace(); }
    catch (JSONException e) { e.printStackTrace(); }
    return null;
}