python - 如何在不使用线程作业更改其位置的情况下更新字符串的值？ [Python]

Question

我的脚本中有两个工作。一旦作业开始，其他作业将异步运行。我为此使用了线程。这个线程将返回一些信息，而其他计算该信息。
我想做的是在计数器的值发生变化的同时，线程也将继续运行。
显示我想要的:

-----------------------------------------
Count: 5
-----------------------------------------
thread keeps running...
thread keeps running...
thread keeps running...

实际上我使用 curses 来实现这个目标模块，但这并不是我想要的。因为当我按 ^C终端内容不见了。我希望他们在屏幕上卡住。
带有诅咒的代码:

import sys
import time
import queue
import signal
import curses
import threading


def ctrl_c_handler(*args):
    sys.exit(0)


signal.signal(signal.SIGINT, ctrl_c_handler)

MESSAGE = "thread keeps running..."


def print_func(message):
    return message


def new_window(stdscr):
    que = queue.Queue()

    curses.curs_set(False)

    y, x = stdscr.getmaxyx()

    draw = x * "-"

    i = 3
    count = 1
    while True:
        thread = threading.Thread(target=lambda q, arg1: q.put(print_func(arg1)), args=(que, MESSAGE,), daemon=True)
        thread.start()
        result = que.get()

        try:
            stdscr.addstr(0, 0, draw)
            stdscr.addstr(1, 0, f"Count: {str(count)}")
            stdscr.addstr(2, 0, draw)
            stdscr.addstr(i, 0, result)

        except curses.error:
            pass

        stdscr.refresh()
        time.sleep(0.1)

        i += 1
        count += 1

        if i == y:
            stdscr.clear()
            i = 3


curses.wrapper(new_window)

有没有办法在不使用诅咒的情况下实现相同的目标，或者在不丢失内容的情况下使用诅咒？
谢谢!

Answer 1

试试这个:

import sys
import time
import queue
import signal
import curses
import threading


ctrl_c_pressed_event = threading.Event()

def ctrl_c_handler(*args):
    ctrl_c_pressed_event.set()


signal.signal(signal.SIGINT, ctrl_c_handler)

MESSAGE = "thread keeps running..."


def print_func(message):
    return message


def new_window(stdscr):
    que = queue.Queue()

    curses.curs_set(False)

    y, x = stdscr.getmaxyx()

    draw = x * "-"

    i = 3
    count = 1
    while True:
        if ctrl_c_pressed_event.isSet():
            stdscr.getkey()
            break
        thread = threading.Thread(target=lambda q, arg1: q.put(print_func(arg1)), args=(que, MESSAGE,), daemon=True)
        thread.start()
        result = que.get()
        try:
            stdscr.addstr(0, 0, draw)
            stdscr.addstr(1, 0, f"Count: {str(count)}")
            stdscr.addstr(2, 0, draw)
            stdscr.addstr(i, 0, result)
        except curses.error:
            pass
        stdscr.refresh()
        time.sleep(0.1)
        i += 1
        count += 1
        if i == y:
            stdscr.clear()
            i = 3


curses.wrapper(new_window)
print('Program ended')