scala - Slick:选项列过滤

Question

我想做这样的事情(这是一个为了简化我的实际问题而编造的例子):

def findByGender(isMale: Option[Boolean]) = {
  People.filter(row => row.name.isNotNull && isMale match {
    case Some(true) => row.wife.isNotNull      // find rows where wife column is not null
    case Some(false) => row.wife.isNull        // find rows where wife column is null
    case None => true                          // select everything
  })    
}

由于最后一个“true”，因此无法编译。有更好的方法吗？

Answer 1

您必须将其设为Column[Boolean]:

def findByGender(isMale: Option[Boolean]) = {
  People.filter(row => row.name.isNotNull && isMale match {
    case Some(true) => row.wife.isNotNull      // find rows where wife column is not null
    case Some(false) => row.wife.isNull        // find rows where wife column is null
    case None => LiteralColumn(true)           // select everything
  })    
}