java - 无法为第二种情况映射 OneToMany 和 ManyToOne？

Question

我正在尝试存储用户发出的订单的集合。一个用户可能有多个订单，但一个订单只有一个用户。这样就形成了1-M关系。 Items 和 ItemOrders 之间也存在相同的关系，ItemOrder 由一个 Item 和一定数量的要订购的 Items 组成。因此，一个 ItemOrder 有一个 Item，但一个 Item 可以有多个 ItemOrder。

在我的测试套件中，我成功地正确创建了 Items 和 ItemOrders。但是，当我扩展测试以创建用户和订单时，我收到“订单”的 SQLSyntaxErrorException...这很奇怪，因为它应该是实现这两种结果的完全相同的过程...而且我不知道是什么我在这里做错了，有什么想法吗？

@Entity
public class ItemEntity implements EntityInt {
    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "item_id", unique = true)
    public int id;

    @OneToMany(mappedBy="item")
    public Set<OrderItemEntity> orderItems = new HashSet<>();

}

@Entity
public class OrderItemEntity implements EntityInt {

    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "order_item_id", unique = true)
    public int id;

    @Column(name = "amount", nullable = false)
    public int amount;

    @ManyToOne
    @JoinColumn(name="item_id", nullable = false)
    private ItemEntity item;

    public OrderItemEntity(ItemEntity item, int amount) {
        this.setItem(item);
        this.amount = amount;
    }

    public void setItem(ItemEntity item) {
        if (this.item != null)
            this.item.orderItems.remove(this);
        this.item = item;
        this.item.orderItems.add(this);
    }
}

@Entity
public class OrderEntity implements EntityInt {

    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "order_id", unique = true)
    public int id;

    @ManyToOne
    @JoinColumn(name="user_id", nullable = false)
    public UserEntity user;

    public UserEntity getUser() {
        return user;
    }

    public void setUser(UserEntity user) {
        if (this.user != null)
            this.user.orders.remove(this);
        this.user = user;
        this.user.orders.add(this);
    }
}

@Entity
public class UserEntity implements EntityInt {

        @Id
        @GeneratedValue(generator = "incrementor")
        @Column(name = "user_id", unique = true)
        public int id;

        @OneToMany(mappedBy="user")
        public Set<OrderEntity> orders = new HashSet<>();

}

测试

@Test
    public void testItemOrderEntity() throws Exception {
         EntityManagerFactory factory = BasicDao.getEntityManagerFactory();
    EntityManager em = factory.createEntityManager();

    em.getTransaction().begin();

    String itemName = Math.random() + "";
    ItemEntity item = new ItemEntity(itemName, 0, 0);
    em.persist(item);

    OrderItemEntity orderItem = new OrderItemEntity(item, 5);
    em.persist(orderItem);

    String uname = "" + Math.random();
    UserEntity user = new UserEntity(uname, uname);
    em.persist(user);

    // Error
    OrderEntity order = new OrderEntity(user);
    em.persist(order);
    em.getTransaction().commit();
    }

EntityInt 包含主要由 BasicDao 用于执行 CRUD 操作的方法。它有 getId()、getVersion()、createVerifyIsUnqieuQuery() 等内容。

BasicDao 是主要的存储库访问类，并由 itemsDao、UsersDao 等扩展。这是测试用例使用的 BasicDao 的相关部分:

BasicDao.java

private static final String PERSISTENCE_UNIT_NAME = "org.hibernate.lab1_web_shop.jpa";

    public static EntityManagerFactory getEntityManagerFactory() {
        return  Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
    }

    public static EntityInt insert(EntityInt entity) throws Exception {
        EntityManagerFactory factory = getEntityManagerFactory();
        EntityManager em = factory.createEntityManager();
        try {
            em.getTransaction().begin();
            Query isUniqueQuery = entity.createVerifyIsUniqueQuery(em);
            if (isUniqueQuery != null) {
                List<EntityInt> resultList = isUniqueQuery.getResultList();
                if (resultList.size() == 0) {
                    entity.beforeInsert(em);
                    em.persist(entity);
                } else {
                    entity = null;
                }
            } else {
                // There is no uniqueness filter so we insert it as is
                entity.beforeInsert(em);
                em.persist(entity);
            }
            em.getTransaction().commit();
            // Returns the persistent entity along with any database modified attributes
            return entity;
        } catch (Exception e) {
            em.getTransaction().rollback();
            throw new Exception(e);
        } finally {
            em.close();
        }
    }

请注意，测试中使用的实体并未真正使用 beforeInsert()。

这是堆栈跟踪:

Caused by: javax.persistence.RollbackException: Error while committing the transaction
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement
Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement
Caused by: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Order (user_id, version, order_id) values (9, 0, 10)' at line 1

我还测试了删除 BasicDao 并在一次提交中完成所有操作，但我仍然重现相同的错误。

Answer 1

"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax error" Hibernate 4

问题是我将我的表命名为“Order”。这是从上面的堆栈跟踪中获得的。