gpt4 book ai didi

java - 不兼容的类型错误: Manipulating return value of another class's method

转载 作者:行者123 更新时间:2023-12-02 09:21:28 25 4
gpt4 key购买 nike

我需要产生一个JsonObject在类里面MainActivity来自方法doInBackground()在类里面Post .

我实例化了类Post ,调用其中正在传递参数的方法,并尝试将其分配给 JSONObject 类型的变量。 .

这是类(class)Post :

class Post extends AsyncTask<String, Void, JSONObject> {

@Override
protected JSONObject doInBackground(String... args) {
JSONObject jsonObject = null;
try {
//Connect to the website
Connection.Response response =
Jsoup.connect(args[0])
.method(Connection.Method.POST)
.data("text", args[1])
.data("language", args[2])
.ignoreContentType(true)
.execute();
Document document = response.parse();
jsonObject = new JSONObject(document.text());
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException err) {
Log.d("Error", err.toString());
}
return jsonObject;
}
}

这就是我尝试检索类 MainActivity 中的对象的方法:

Post post = new Post();
JSONObject object = post.execute(stringurl, text, "en");

我收到的 Java 错误是类型不兼容。必需的是 org.json.JSONObject发现是android.os.AsyncTask <java.lang.String, java.lang.Void, org.json.JSONObject> .

我应该能够捕获JSONObject ...如何?

最佳答案

您可以在 MainActivity 中声明一个方法,一旦获取了 JSONObject,就可以从 AsyncTask 调用该方法:

private onObtainJSONObject(JSONObject jsonObject){
if(jsonObject != null){
// do something with the JSONObject
} else{
// something went wrong - maybe show an error message?
}
}

并且您需要重写AsyncTask中的onPostExecute():

public void onPostExecute(JSONObject jsonObject){
// Note: this will be executed on the main thread
MainActivity.this.onObtainJSONObject(jsonObject);
}

如果AsyncTask不是您的Activity的内部类,您可以使用回调(一个简单的接口(interface)),如下所示

public interface PostCallback{
void onSuccess(JSONObject data);
void onError(Exception exception);
}

然后让 AsyncTask 有一个 PostCallback 类型的字段和一个 setter setCallback(PostCallback)

MainActivity中:

Post post = new Post();
post.setPostCallback(new PostCallback(){

@Override
onSuccess((JSONObject data){
onObtainJSONObject(data);
}

@Override
onError(Exception exception){
// exception handling ...
}
});
JSONObject object = post.execute(stringurl, text, "en");

帖子中:

private PostCallback callback;
private Exception exception;

public setPostCallback(PostCallback callback){
this.callback = callback;
}

@Override
protected JSONObject doInBackground(String... args){
// keep everything as before but when an Exception occurs,
// assign it to *exception* in the catch block
}

@Override
public void onPostExecute(JSONObject jsonObject){
// Note: this will be executed on the main thread
if(exception == null){
callback.onSuccess(jsonObject);
} else {
callback.onError(exception);
}
}

关于java - 不兼容的类型错误: Manipulating return value of another class's method,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58665239/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com