java - 在 Java 中创建示例时可以使用 "linked list"吗？

Question

创建实例时可以使用链表吗？

示例:

我有 Main 类和一个 Employee 类。

主类:

 Employee a1 = new Employee();

当我们创建Instance时，通常会这样写代码。

但是我想知道是否有任何方法可以使用链表创建实例。

像这样:

LinkedList<String> alist = new LinkedList<String>();  
Employee alist(index) = new Employee();

Answer 1

您已经创建了 List<String> ，它不能容纳 Employee 的实例，但也许他们的名字......

您似乎想要这样的东西:

Employee employee = new Employee();
// maybe set some attributes (the next line is a guess due to a lack of information)
employee.setName("E. M. Ployee");

// create a list of employees
List<Employee> employees = new LinkedList<>();
// and add the employee
employees.add(employee);

如果您有 List<String>和一个 class Employee看起来和这个很相似

class Employee {

    private String name;

    public Employee(String name) {
        this.name = name;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

然后你可以创建 Employee 的实例对于名称列表中的每个名称:

public static void main(String[] args) {
    // create a list of names (String)
    List<String> names = new LinkedList<>();
    names.add("E. M. Ployee");
    names.add("U. R. Fired");
    // create a list of employees (Employee)
    List<Employee> employees = new LinkedList<>();
    // go through the names and create an Employee for each one
    names.forEach(name -> employees.add(new Employee(name)));
    // then print the names from the employee objects that are in the list of employees
    employees.forEach(employee -> System.out.println(employee.getName()));
}