java - 获取文件名(手机存储/下载文件夹中的图像)

Question

下载的图像显示如下所示的 uridat=content://com.android.providers.downloads.documents/document/22

而 get filename ==>22 显示为文件名，这会给出异常错误java.io.FileNotFoundException:/storage/emulated/0/Download/22:打开失败:ENOENT(没有这样的文件或目录)

但我需要确切的文件名，即 img.dcm

        Uri uri = data.getData();
        String path = uri.getPath() ;

        File fpath = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS  ) ;
        String filename = path.substring(path.lastIndexOf("/")+1);
        Log.d(TAG, "filename-----"+filename);
        Log.d(TAG, "path-----"+path);
        //File f = new File("content://com.android.externalstorage.documents/document/0BF4-3218:dicom/2.dcm");
        File f = new File(fpath,filename);
        String dicomFile =   fpath +"/"+ filename ; //"D:\\JavaProjects\\Sample Images\\MR-MONO2-16-head";
        Log.d(TAG, "dicomFile-----"+dicomFile);

Answer 1

您可以使用此方法获取文件名

public String getName(String filename) {
    if (filename == null) {
        return null;
    }
    int index = filename.lastIndexOf('/');
    return filename.substring(index + 1);
}

在此消息中将您的 URI 作为参数传递

getName(uri.toString());