scala - Spark 任务不可序列化

Question

我已经尝试了在 StackOverflow 上找到的该问题的所有解决方案，但尽管如此，我还是无法解决它。我有一个“MainObj”对象，它实例化“推荐”对象。当我调用“recommendationProducts”方法时，我总是收到错误。该方法的代码如下:

def recommendationProducts(item: Int): Unit = {

val aMatrix = new DoubleMatrix(Array(1.0, 2.0, 3.0))

def cosineSimilarity(vec1: DoubleMatrix, vec2: DoubleMatrix): Double = {
  vec1.dot(vec2) / (vec1.norm2() * vec2.norm2())
}

val itemFactor = model.productFeatures.lookup(item).head
val itemVector = new DoubleMatrix(itemFactor)

//Here is where I get the error:
val sims = model.productFeatures.map { case (id, factor) =>
  val factorVector = new DoubleMatrix(factor)
  val sim = cosineSimilarity(factorVector, itemVector)
  (id, sim)
}

val sortedSims = sims.top(10)(Ordering.by[(Int, Double), Double] {
  case (id, similarity) => similarity
})

println("\nTop 10 products:")
sortedSims.map(x => (x._1, x._2)).foreach(println)

这是错误:

Exception in thread "main" org.apache.spark.SparkException: Task not serializable
at org.apache.spark.util.ClosureCleaner$.ensureSerializable(ClosureCleaner.scala:298)
at org.apache.spark.util.ClosureCleaner$.org$apache$spark$util$ClosureCleaner$$clean(ClosureCleaner.scala:288)
at org.apache.spark.util.ClosureCleaner$.clean(ClosureCleaner.scala:108)
at org.apache.spark.SparkContext.clean(SparkContext.scala:2094)
at org.apache.spark.rdd.RDD$$anonfun$map$1.apply(RDD.scala:370)
at org.apache.spark.rdd.RDD$$anonfun$map$1.apply(RDD.scala:369)
at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151)
at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:112)
at org.apache.spark.rdd.RDD.withScope(RDD.scala:362)
at org.apache.spark.rdd.RDD.map(RDD.scala:369)
at RecommendationObj.recommendationProducts(RecommendationObj.scala:269)
at MainObj$.analisiIUNGO(MainObj.scala:257)
at MainObj$.menu(MainObj.scala:54)
at MainObj$.main(MainObj.scala:37)
at MainObj.main(MainObj.scala)
Caused by: java.io.NotSerializableException: org.apache.spark.SparkContext
Serialization stack:
- object not serializable (class: org.apache.spark.SparkContext, value: org.apache.spark.SparkContext@7c2312fa)
- field (class: RecommendationObj, name: sc, type: class org.apache.spark.SparkContext)
- object (class MainObj$$anon$1, MainObj$$anon$1@615bad16)
- field (class: RecommendationObj$$anonfun$37, name: $outer, type: class RecommendationObj)
- object (class RecommendationObj$$anonfun$37, <function1>)
at org.apache.spark.serializer.SerializationDebugger$.improveException(SerializationDebugger.scala:40)
at org.apache.spark.serializer.JavaSerializationStream.writeObject(JavaSerializer.scala:46)
at org.apache.spark.serializer.JavaSerializerInstance.serialize(JavaSerializer.scala:100)
at org.apache.spark.util.ClosureCleaner$.ensureSerializable(ClosureCleaner.scala:295)
... 14 more

我尝试添加:1)“将 Serialized 扩展”(Scala)到我的类2)“扩展java.io.Serialized”到我的类3)“@transient”到某些部分4)获取此类中的模型(和其他功能)(现在我从其他对象获取它们，然后将它们像参数一样传递给我的类)

如何解决？我快要疯了!预先感谢您!

Answer 1

key 在这里:

 field (class: RecommendationObj, name: sc, type: class org.apache.spark.SparkContext)

因此，您有一个名为 sc 且类型为 SparkContext 的字段。 Spark想要序列化该类，因此他尝试也序列化所有字段。

你应该:

• 使用@transient注释并检查是否为null，然后重新创建
• 不使用字段中的 SparkContext，而是将其放入方法的参数中。但请记住，您永远不应该在 map、flatMap 等的闭包内使用 SparkContext。