java - Spring security antMatcher 不起作用

Question

编辑:

我进一步深入研究了问题，发现即使使用单一配置，问题仍然存在。如果我使用单一配置并保留

http.antMatcher("/api/test/**")

网址不安全。删除 antMatcher 和 antMatchers 会立即保护 url。即如果我使用:

http.httpBasic()
    .and()
    .authorizeRequests()
    .anyRequest()
    .authenticated();

那么只有 Spring Security 正在保护 url。为什么 antMatcher 无法运行？

(更新了标题以包含实际问题。)

<小时/>

原帖:

我提到了以下 stackoverflow 问题:

1. Spring REST security - Secure different URLs differently

2. Using multiple WebSecurityConfigurerAdapter with different AuthenticationProviders (basic auth for API and LDAP for web app)

和 Spring Security 文档:

https://docs.spring.io/spring-security/site/docs/current/reference/htmlsingle/#multiple-httpsecurity

但我无法配置多个 http 安全元素。当我遵循官方 spring 文档时，它在我的情况下才有效，因为第二个 http 安全元素是包罗万象的，但是一旦我添加特定的 url，就可以访问所有 url，无需任何身份验证。

这是我的代码:

@EnableWebSecurity
@Configuration
public class SecurityConfig {

    @Bean                                                             
    public UserDetailsService userDetailsService() throws Exception {
        InMemoryUserDetailsManager manager = new InMemoryUserDetailsManager();
        manager.createUser(User.withUsername("user").password("userPass").roles("USER").build());
        manager.createUser(User.withUsername("admin").password("adminPass").roles("ADMIN").build());
        return manager;
    }


    @Configuration
    @Order(1)                                                        
    public static class ApiWebSecurityConfigurationAdapter extends WebSecurityConfigurerAdapter {

        @Override       
        public void configure(AuthenticationManagerBuilder auth) 
          throws Exception {            
            auth.inMemoryAuthentication().withUser("user").password("user").roles("USER");
            auth.inMemoryAuthentication().withUser("admin").password("admin").roles("ADMIN");
        }

        protected void configure(HttpSecurity http) throws Exception {
            http
                .antMatcher("/api/v1/**")                               
                .authorizeRequests()
                .antMatchers("/api/v1/**").authenticated()
                    .and()
                .httpBasic();
        }
    }

    @Configuration
    @Order(2)
    public static class FormLoginWebSecurityConfigurerAdapter extends WebSecurityConfigurerAdapter {

        @Override       
        public void configure(AuthenticationManagerBuilder auth) 
          throws Exception {

            auth.inMemoryAuthentication().withUser("user1").password("user").roles("USER");
            auth.inMemoryAuthentication().withUser("admin1").password("admin").roles("ADMIN");
        }

        @Override
        protected void configure(HttpSecurity http) throws Exception {
            http
                .antMatcher("/api/test/**")
                .authorizeRequests()
                .antMatchers("/api/test/**").authenticated()
                    .and()
                .formLogin();
        }
    }
}

现在任何网址都可以访问了。如果我从第二个配置中删除 antMatcher，所有网址都会受到保护。

Answer 1

该模式不得包含上下文路径，请参阅AntPathRequestMatcher :

Matcher which compares a pre-defined ant-style pattern against the URL ( servletPath + pathInfo) of an HttpServletRequest.

和HttpServletRequest.html#getServletPath :

Returns the part of this request's URL that calls the servlet. This path starts with a "/" character and includes either the servlet name or a path to the servlet, but does not include any extra path information or a query string. Same as the value of the CGI variable SCRIPT_NAME.

和HttpServletRequest.html#getContextPath :

Returns the portion of the request URI that indicates the context of the request. The context path always comes first in a request URI. The path starts with a "/" character but does not end with a "/" character. For servlets in the default (root) context, this method returns "". The container does not decode this string.

您修改和简化的代码:

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
            .antMatcher("/test/**")
            .authorizeRequests()
                .anyRequest().authenticated()
                .and()
            .formLogin();
    }