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scala - unsupportedOperationException 使用 Joda 时间将字符串转换为 DateTime 时出错

转载 作者:行者123 更新时间:2023-12-02 09:14:18 25 4
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我正在使用 joda.time.Datetime 库将字符串转换为日期时间字段,但它会抛出不受支持的异常这是主类代码:

//create new var with input data without header
var inputDataWithoutHeader: RDD[String] = dropHeader(inputFile)
var inputDF1 = inputDataWithoutHeader.map(_.split(",")).map{p =>
val dateYMD: DateTime = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss").parseDateTime(p(8))
testData(dateYMD)}.toDF().show()

p(8) 是在类 testData 中定义的数据类型日期时间的列,该列的 CSV 数据的值类似于 2013-02-17 00:00:00

这是 testData 类:

case class testData(StartDate: DateTime) { }

这是我得到的错误:

线程“主”中的异常

java.lang.UnsupportedOperationException: Schema for type org.joda.time.DateTime is not supported
at org.apache.spark.sql.catalyst.ScalaReflection$class.schemaFor(ScalaReflection.scala:153)
at org.apache.spark.sql.catalyst.ScalaReflection$.schemaFor(ScalaReflection.scala:29)
at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun$schemaFor$1.apply(ScalaReflection.scala:128)
at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun$schemaFor$1.apply(ScalaReflection.scala:126)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:244)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:244)
at scala.collection.immutable.List.foreach(List.scala:318)
at scala.collection.TraversableLike$class.map(TraversableLike.scala:244)
at scala.collection.AbstractTraversable.map(Traversable.scala:105)
at org.apache.spark.sql.catalyst.ScalaReflection$class.schemaFor(ScalaReflection.scala:126)
at org.apache.spark.sql.catalyst.ScalaReflection$.schemaFor(ScalaReflection.scala:29)
at org.apache.spark.sql.catalyst.ScalaReflection$class.schemaFor(ScalaReflection.scala:64)
at org.apache.spark.sql.catalyst.ScalaReflection$.schemaFor(ScalaReflection.scala:29)
at org.apache.spark.sql.SQLContext.createDataFrame(SQLContext.scala:361)
at org.apache.spark.sql.SQLImplicits.rddToDataFrameHolder(SQLImplicits.scala:47)
at com.projs.poc.spark.ml.ProcessCSV$delayedInit$body.apply(ProcessCSV.scala:37)

最佳答案

  1. 正如您在 the official documentation 中所读到的那样Spark SQL 中的日期使用 java.sql.Timestamp 表示。如果你想使用 Joda 时间,你必须将输出转换为正确的类型

  2. SparkSQL 可以使用类型转换轻松处理标准日期格式:

    sc.parallelize(Seq(Tuple1("2016-01-11 00:01:02")))
    .toDF("dt")
    .select($"dt".cast("timestamp"))

关于scala - unsupportedOperationException 使用 Joda 时间将字符串转换为 DateTime 时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34796176/

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