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scala - 避免递归 MTL 类上的隐式扩展发散

转载 作者:行者123 更新时间:2023-12-02 09:12:47 26 4
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我正在尝试使用 Hlist 在 cats mtl 中创建可组合状态类型,并定义了 MonadState 如下

implicit def hlistStateMonad[M[_], S <: HList, S2]
(implicit S:Selector[S, S2], R:Replacer[S, S2, S2], M:MonadState[M, S]):MonadState[M, S2]

然而,即使 S2 不是 HList,并且 Selector 和 Replacer 无法解析并且它不会在cats.mtl 隐式

我尝试定义 S2 <:!< HList (和 =:!=),但这根本没有帮助。

可测试的代码如下所示:

object Test {
implicit def hlistStateMonad[M[_], S <: HList, S2](implicit S:Selector[S, S2], R:Replacer[S, S2, S2], M:MonadState[M, S]):MonadState[M, S2] =
new MonadState[M, S2] {

val monad: Monad[M] = M.monad

def inspect[A](f: S2 => A):M[A] =
M.inspect(s => f(S(s)))

def modify(f: S2 => S2):M[Unit] =
M.modify(s => R(s, f(S(s))).asInstanceOf[(S2, S)]._2)

def get:M[S2] =
M.inspect(S.apply)

def set(s2: S2): M[Unit] =
M.modify(s => R(s, s2).asInstanceOf[(S2, S)]._2)
}
}

test("Monad state resolution with HList") {

type M[V] = State[Int :: String :: HNil, V]

import cats.mtl.instances.all._
import Test._

val m = implicitly[MonadState[M, Int]]
}

最佳答案

添加查找 S2 不是 HList 的证据(如您所建议的)并在选择器和替换器之前查找 MonadState 似乎对我来说已经成功了。

怀疑这可能与编译器没有将 S 绑定(bind)到任何东西有关 - 只是知道它的上限是 HList 。(但这是我最好的猜测)

希望这有帮助。

import cats.Monad
import cats.data.State
import cats.mtl.MonadState
import org.scalatest.{FlatSpec, Matchers}
import shapeless._
import shapeless.::
import shapeless.ops.hlist.{Replacer, Selector}
import cats.mtl.instances.all._

class Test extends FlatSpec with Matchers {

implicit def hlistStateMonad[M[_], S <: HList, S2](
implicit
nEv: S2 <:!< HList,
M: MonadState[M, S],
S: Selector[S, S2],
R: Replacer[S, S2, S2]): MonadState[M, S2] =
new MonadState[M, S2] {

val monad: Monad[M] = M.monad

def inspect[A](f: S2 => A): M[A] =
M.inspect(s => f(S(s)))

def modify(f: S2 => S2): M[Unit] =
M.modify(s => R(s, f(S(s))).asInstanceOf[(S2, S)]._2)

def get: M[S2] =
M.inspect(S.apply)

def set(s2: S2): M[Unit] =
M.modify(s => R(s, s2).asInstanceOf[(S2, S)]._2)
}

"Monad state resolution with HList" should "compile and maybe even run?" in {

type M[V] = State[Int :: String :: HNil, V]

val m = implicitly[MonadState[M, Int]]

val res = for {
a <- m.set(5)
b <- m.get
} yield b + 1

res.run(1 :: "test" :: HNil).value._2 shouldBe 6
}
}

关于scala - 避免递归 MTL 类上的隐式扩展发散,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50271244/

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