arrays - 对数组进行排序 命令式 ocaml

Question

我正在做一个相当简单的示例来学习如何使用 ocaml 作为命令式语言。我的猜测是我搞乱了分号，但我在代码中找不到任何错误

let sort array = 
for index = 0 to (Array.length array -1) do
    let boole = ref false;
    let pos = ref index;
    let max = ref array.(index); 
    let p = ref !pos;
    let m = ref !max;
    while !pos <> (Array.lenght array -1 ) do
        if array.(!pos) > !max then begin
            max := array(!pos); 
            boole := true;
            p := !pos
        end
        pos := !pos + 1
    done;
    if (!boole = true) then begin
        array.(index) <- max;
        array.(pos) <- m
    end
done ;;

谢谢。

编辑1:

如果有人遇到这个问题，我将发布正确的代码，因为即使使用正确的语法，上述代码也无法正确对数组进行排序:

let sort array =
for index = 0 to (Array.length array -1) do
let boole = ref false in
let pos = ref index in
let max = ref array.(index) in
let p = ref !pos in
let m = ref !max in    
for i = !pos to (Array.length array -1) do
  if (array.(i) > !max) then begin
    pos :=i;    
    max := array.(!pos);
    boole := true;
  end;
done;
if (!boole = true) then begin
    array.(!pos) <- !m;
    array.(!p) <- !max;
end;  
done ;;

Answer 1

首先，OCaml 中没有 let x = y; 表达式，正确的语法是 let x = y in，你也不应该忘记取消引用您的引用文献。

let sort array =
  for index = 0 to (Array.length array -1) do
    let boole = ref false in
    let pos = ref index in
    let max = ref array.(index) in
    let p = ref !pos in
    let m = ref !max in
    while !pos <> (Array.length array -1 ) do
      if array.(!pos) > !max then begin
        max := array.(!pos);
        boole := true;
        p := !pos
      end;
      pos := !pos + 1;
    done;
    if (!boole = true) then begin
      array.(index) <- !max;
      array.(!pos) <- !m;
    end;
  done ;;