Anaconda:导航器启动时发生意外错误

Question

我已经安装了 Anaconda，我已经成功启动它，然后使用 R 或 python，今天我无法再启动它并收到此错误(当我在管理员模式下运行该软件时，我收到相同的错误)

An unexpected error ocurred on Navigator start-up
psutil.AccesDenied(pid=5740)

Traceback (most recent call last):
File "C:\Users\user\Anaconda3\lib\site-packages\psutil\_pswindows.py", line 620, in wrapper
return fun(self, *args, **kwargs)
File "C:\Users\user\Anaconda3\lib\site-packages\psutil\_pswindows.py", line 690, in cmdline
ret = cext.proc_cmdline(self.pid)
PermissionError: [WinError 5] Access Denied

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "C:\Users\user\Anaconda3\lib\site-packages\anaconda_navigator\exceptions.py", line 75, in exception_handler
return_value = func(*args, **kwargs)
File "C:\Users\user\Anaconda3\lib\site-packages\anaconda_navigator\app\start.py", line 108, in start_app
if misc.load_pid() is None: # A stale lock might be around
File "C:\Users\user\Anaconda3\lib\site-packages\anaconda_navigator\utils\misc.py", line 384, in load_pid
cmds = process.cmdline()
File "C:\Users\user\Anaconda3\lib\site-packages\psutil\__init__.py", line 701, in cmdline
return self._proc.cmdline()
File "C:\Users\user\Anaconda3\lib\site-packages\psutil\_pswindows.py", line 623, in wrapper
raise AccessDenied(self.pid, self._name)
psutil.AccessDenied: psutil.AccessDenied (pid=5740) 

Answer 1

我遵循以下建议: https://github.com/ContinuumIO/anaconda-issues/issues/6006, https://github.com/ContinuumIO/anaconda-issues/issues/1984

这些命令帮助了我:

conda update anaconda-navigator
conda update navigator-updater
anaconda-navigator --reset